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3 years ago

Which best describes a difference between laser light and regular light?

1 answer:

4 0

The basic difference is that the ordinary sources are incoherent that means that the discrete frequencies merge up to give an intermediate between the maximum and minimum frequencies. While the laser is coherent containing the single frequency with maximum amplitude. thus travelling far.

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Light of wavelength 650 nm is normally incident on the rear of a grating. The first bright fringe (other than the central one) i

garik1379 [7]

Answer

given,

wavelength (λ) = 650 nm

angle = 5°

using bragg's law

$sin \theta = \dfrac{n \lambda}{d}$

$d= \dfrac{n \lambda}{sin \theta}$

$d= \dfrac{1 \times 650 \times 10^{-9}\ m}{sin5^0}$

d = 7.46 x 10⁻⁴ cm

number of slits per centimeter

= $\dfrac{1}{d}\\\Rightarrow \dfrac{1}{7.46\times 10^{-4}}\\\Rightarrow 1340 split per centimeter.$

b) wavelength of two rays 650 nm and 420 nm

$d = \dfrac{1}{5000}$

d = 2 x 10⁻6 m

we now,

$sin \theta = \dfrac{n \lambda}{d}$

for 650 nm

$sin \theta = \dfrac{2\times 650\times 10^{-9}}{2\times 10^{-6}}$

$\theta =sin^{-1}(0.65)$

θ = 40.54°

for 450 nm

$sin \theta = \dfrac{2\times 450\times 10^{-9}}{2\times 10^{-6}}$

$\theta =sin^{-1}(0.45)$

θ = 24.83°

now, difference

|θ_{650} -θ_{420}| =40.54°-24.83°

|θ_{650} -θ_{420}| =19.71°

8 0

4 years ago

Compare and contrast the sound waves produced by someone whispering and someone shouting.

andrezito [222]

1. They could have different types of sounds, so wave-shape could be different.

2. If they have the same frequency, the volume is different, so they could have different amplitudes (larger amplitude = larger sound).

3. Different frequencies based on the pitches

4 0

4 years ago

Que carro ese que está en la foto

Taya2010 [7]

Travis Scott!3&;8284$28&:!;&29395

7 0

3 years ago

Read 2 more answers

What happens to jetstream’s as they get closer to the equator

MAVERICK [17]

Answer:They stop because jet streams follow boundaries between hot and cold air.

Explanation:

6 0

4 years ago

Read 2 more answers

Resistance to the motion of an automobile consists of road friction, which is almost independent of speed, and air drag, which i

Troyanec [42]

Answer:

73.52983 Hp

Explanation:

m = Mass of car = $\dfrac{W}{g}$

W = Weight of car = 12000 N

a = Acceleration = 0.96 m/s²

Velocity of the car

$v=82\times \dfrac{1000}{3600}\\\Rightarrow v=\dfrac{82}{3.6}\\\Rightarrow v=\dfrac{41}{1.8}$

From the question

$F=300+1.8v^2\\\Rightarrow F=300+1.8\times \left(\dfrac{41}{1.8}\right)^2\\\Rightarrow F=1233.88\ N$

Balancing the forces

$\dfrac{P}{v}-1233.88=ma\\\Rightarrow P=(ma+12000)v\\\Rightarrow P=\left(\dfrac{12000}{9.81}\times 0.96+1233.88\right)\dfrac{41}{1.8}\\\Rightarrow P=54853.26055\ W=\dfrac{54853.26055}{746}\\\Rightarrow P=73.52983\ Hp$

The power is 73.52983 Hp

6 0

4 years ago