Answer:
2.4 m
Explanation:
Consider the motion along the vertical direction
= initial position of ball above the ground = 4.5 m
= time taken by the ball to hit the smokestack = 0.65 s
= initial velocity of the ball along vertical direction
= acceleration due to gravity = - 9.8 m/s²
= position of ball at the time of hitting the smokestack
Using the kinematics equation
inserting the above values
Answer:
Explanation:
Initial velocity is 0. In the equation v = v0+at where v0 is the initial velocity of 0, we only have to fill in -9.8 for a and 2 for t to get the velocity after 2 seconds -19.6 m/s; after 5 seconds, when it hits the ground, a = -9.8 and t = 5 to give a velocity of -49 m/s. Gravity pulls down everything at the same rate, it doesn't matter whether we drop a feather or an elephant from the window!
Answer:
h≅ 58 m
Explanation:
GIVEN:
mass of rocket M= 62,000 kg
fuel consumption rate = 150 kg/s
velocity of exhaust gases v= 6000 m/s
Now thrust = rate of fuel consumption×velocity of exhaust gases
=6000 × 150 = 900000 N
now to need calculate time t = amount of fuel consumed÷ rate
= 744/150= 4.96 sec
applying newton's law
M×a= thrust - Mg
62000 a=900000- 62000×9.8
acceleration a= 4.71 m/s^2
its height after 744 kg of its total fuel load has been consumed
h= 58.012 m
h≅ 58 m
Answer:
A. gas only
Explanation:
In a gas, the molecules are in continuous, random, straight-line motion.
The molecules are independent of one another i.e The forces of attraction (cohesive forces) and repulsion between the molecules are small and negligible,As such they possess greater kinetic energy which allows them to break the force of attraction between them
In liquid, the molecules have a less random pattern of motion and they can only slide past one another.
In solid, the motion are restricted to a small place as the molecules are not free to move about but merely vibrate about their lattice points.
<span>if we take ball then the Kinetic Energy of the ball is ½mV²
as it rolls up the slope, the Kinetic Energy is converted to potential energy, PE = mgh.
mgh = ½mV²
h = V²/2g</span>
