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Gala2k [10]
3 years ago
7

A 6 kg object falls 10 m. The object is attached mechanically to a paddle-wheel which rotates as the object falls. The paddle-wh

eel is immersed in 600 g of water at 15°C. What is the maximum temperature that the water could be increased to? Is this a very efficient way of heating water? The specific heat of water is 4.186 J/(g* ˚C).
Physics
1 answer:
maksim [4K]3 years ago
5 0

Answer:16.234^{\circ}C

Explanation:

Given

Mass of object (m)=6 kg

falling height(h)=10 m

mass of water(m_w)=600 gm

temperature of water =15

specific heat of water =4.186 j/g-^{\circ}C

Let T be the Final Temperature of water

Here Object Potential Energy is converted into Heat energy which will be absorbed by water

Potential Energy(P.E.)=mgh=6\times 9.81\times 10=588.6 J

Heat supplied=m_wc(\Delta T)

H.E.=600\times 4.186\times (T-16)

588.6=2511.6\times (T-16)

T-16=0.234

T=16.234^{\circ}C

This is not an efficient way of heating water as there is only0.234^{\circ}Cincrease in temperature.

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