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Anettt [7]
3 years ago
14

A steam flows from high elevation to low elevation very quickly, has steep canyon walls, and rapidly moving water. What type of

stream is it?
A.Old stream
B.Mature stream
C.Youthful stream
D.rejuvenated stream
Physics
1 answer:
QveST [7]3 years ago
7 0

Correct option: D. Rejuvenated stream

The mature stream have medium velocity and the canyon walls are not steep.

The old stream have water moving at very slow pace and it has wide floodplain.

The youthful stream have narrow and steep canyon walls and the water is fast moving.

The rejuvenated stream is formed due to uplift of land raised by tectonic activity. The water flows very quickly from high elevation to low elevation and the water moves rapidly. It also have steep canyon walls.

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Serga [27]

Answer:

B

Explanation:

Heat flows from hot to cold to lower the temperature of hot areas and increase temperature of cold areas. The end result is that the 2 areas have the same temperature, thus increasing entropy.

7 0
3 years ago
what would the net force be on the box in the problems shown below.( both force and direction).​ for all four diagrams. please e
DIA [1.3K]

Answer:
A) object moves 20 N [West] or -20 N [East]
B) object moves 6 N [South] or -6 N [North]
C) object moves 90 N [West] or -90 N [East]
D) object does not move and is at rest*

*Rest means 0


Why:

A)both forces from north and south that are pushing against the object neutralize each other. Assume that north is positive and south is negative: 20 [N] + (-20) [S] = 0
On West and east, you can see that west has a greater force. Assume that west is negative and east is positive: 50 [E] + (-70) [W] = -20 [E]
8 0
3 years ago
Two objects, one with a mass of and the other with a force of 30.0kg experience a gravitational force of attraction of 7.50 * 10
nydimaria [60]

Answer:

Explanation:

The formula for this is

F_g=\frac{Gm_1m_2}{r^2} where F is the gravitational force, G is the gravitational constant, m1 is the mass of one object and m2 is the mass of the other object. We are looking for r, the distance between the centers of their masses.

Filling in:

7.5*10^{-8}=\frac{6.67*10^{-11}(90.0)(30.0)}{r^2} and moving things around to solve for r:

r=\sqrt{\frac{6.67*10^{-11}(90.0)(30.0)}{7.5*10^{-8}} } Doing all that and rounding to the 3 sig fig's you need gives us a distance of 1.55 m

8 0
3 years ago
UCaShoTLLOuuj9D4vqFtTpSQ<br><br> search
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Explanation:

4 0
3 years ago
A car traveling at a speed of 50.0 m/s encounters an emergency and comes to a complete stop. How much time will it take for the
ludmilkaskok [199]

Answer:

t=1.25s

Explanation:

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V0= 0 m/s

a= - 4m/s2

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6 0
3 years ago
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