All categories

2 years ago

_Na+ Cl2 - -> _NaCl A 2,4 B 1,2 C 3,3 D 2,2

Chemistry

1 answer:

Natali [406]2 years ago

4 0

Answer:

D 2,2

Explanation:

We can see that there are 2 chlorines on the reactant side so there has to be a 2 on the product side

Now we have Na + Cl2 --> 2NaCl

The problem now is that there are 2 sodiums on the product side so add a 2 to the Na on the reactant side

2Na + Cl2 --> 2NaCl

Now it's balanced!

You might be interested in

Which element would you expect to behave the most like carbon (C)?

vesna_86 [32]

Answer:

Explanation:

Germanium and Carbon are in the same 14th group.

3 0

3 years ago

Read 2 more answers

A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil

Flura [38]

Answer: Molarity of $Cl^-$ anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles$

$V_s$ = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L$

Therefore, the molarity of solution will be $5.2\times 10^{-3}mole/L$

$MgCl_2\rightarrow Mg^{2+}+2Cl^-$

As 1 mole of $MgCl_2$ gives 2 moles of $Cl^-$

Thus $5.2\times 10^{-3}$ moles of $MgCl_2$ gives = $\frac{2}{1}\times 5.2\times 10^{-3}=0.0104$

Thus the molarity of $Cl^-$ anions in the chemist's solution is 0.0104 M

6 0

3 years ago

The number 0.00003007 expressed in exponential notation is

antiseptic1488 [7]

The exponential is 3.007 times 10 to the -5

5 0

3 years ago

Please help me with this question!!

mestny [16]

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$ $\text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles$

$2Na+Cl_2\rightarrow 2NaCl$

According to stoichiometry :

1 mole of $Cl_2$ produce = 2 moles of $NaCl$

Thus 7.04 moles of $Cl_2$ will produce= $\frac{2}{1}\times 7.04=14.08moles$ of $NaCl$

Mass of $NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g$

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

3 0

3 years ago

Describe the factors that affect the force of gravity

guajiro [1.7K]

Answer:

gravity

Explanation:

gravity

7 0

2 years ago