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makvit [3.9K]
3 years ago
12

Heating 2.40 g of the oxide of metal X (molar mass of X = 55.9 g/mol) in carbon monoxide (CO) yields the pure metal and carbon d

ioxide. The mass of the metal product is 1.68 g. From the data given, show that the simplest formula of the oxide is X2O3 and write a balanced equation for the reaction.
Chemistry
1 answer:
Korolek [52]3 years ago
8 0

Answer:The molecular formula of the oxide of metal be X_2O_3. The balanced equation for the reaction is given by:

X_2O_3+3CO\rightarrow 3CO_2+2X

Explanation:

Let the molecular formula of the oxide of metal be X_2O_y

X_2O_y+yCO\rightarrrow yCO_2+2X

Mass of metal product = 1.68 g

Moles of metal X =\frac{1.68 g}{55.9 g/mol}=0.03005 mol

1 mol of metal oxide produces 2 moles of metal X.

Then 0.03005 moles of metal X will be produced by:

\frac{1}{2}\times 0.03005 mol=0.01502 mol of metal oxide

Mass of 0.01502 mol of metal oxide = 2.40 g (given)

0.01502 mol\times (2\times 55.9 g/mol+y\times 16 g/mol)=2.40 g

y = 2.999 ≈ 3

The molecular formula of the oxide of metal be X_2O_3. The balanced equation for the reaction is given by:

X_2O_3+3CO\rightarrow 3CO_2+2X

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