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KiRa [710]
2 years ago
5

According to Niels Bohr, electrons travel around an atom's nucleus in well-defined orbits.

Chemistry
2 answers:
Rainbow [258]2 years ago
7 0

Answer:

..........

Explanation:

Bas_tet [7]2 years ago
5 0

Answer: The answer is B

Explanation:

can i get brainliest?

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Phantasy [73]
Pressure, volume, temperature, # moles Pressure, volume and temperature, and moles of gas


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8 0
3 years ago
50 pts! Please help, much appreciated (:
Korolek [52]

Answer:

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4 0
3 years ago
Write the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate. 2
Margarita [4]
<span>Benzoin<span> is an organic compound with the formula PhCH(OH)C(O)Ph. It is a hydroxy ketone attached to two phenyl groups.</span><span>

To answer your question, </span><span>the balanced oxidation-reduction reaction equation for the oxidation of benzoin by ammonium nitrate is:

</span>2Ph-C(OH)-C(O)-Ph+NH4NO3 --> 2Ph-C(O)-C(O)-Ph + N2 + 3H2O.</span>

<span>
</span><span>I hope this helps and if you have any further questions, please don’t hesitate to ask again.</span>

7 0
3 years ago
The amount of matter in a object is referred as:
mestny [16]
Volume is the thing
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4 0
3 years ago
4.1 moles of sodium carbonate to molecules of sodium carbonate.​
docker41 [41]
<h3>Answer:</h3>

2.47 × 10^24 molecules

<h3>Explanation:</h3>

One mole of a compound contains molecules equivalent to the Avogadro's number, 6.022 × 10^23.

That is, 1 mole of a compound =  6.022 × 10^23 molecules

Therefore,

1 mole of Na₂CO₃ = 6.022 × 10^23 molecules

Thus, we can calculate the number of molecules in 4.1 moles of Na₂CO₃

we get,

 = 4.1 moles × 6.022 × 10^23 molecules

 = 2.47 × 10^24 molecules

Hence, 4.1 moles of Na₂CO₃ contains 2.47 × 10^24 molecules

3 0
3 years ago
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