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densk [106]
2 years ago
12

Which of these is MOST LIKELY to contribute to the long-term instability of a local ecosystem? A) storms that uproot large trees

in the area B) introduction of a non-native animal species C) seasonal migration of birds to and from the ecosystem D) flash floods that destroy the nests of local water birds
Chemistry
2 answers:
Amanda [17]2 years ago
6 0
The most damaging event is B) introduction of a non-native animal species.

There are multiple cases in recorded history where invasive species have ruined ecosystems and even driven some species to extinction. An example of this is the dodo bird which went extinct due partially due to the invasion of rats into their habitats.
Salsk061 [2.6K]2 years ago
5 0

B) introduction of a non-native animal species

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True or false(Internal forces act on the outside of an object, and external forces act within an object.)
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False I’m not sure exactly
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What is 316 Kelvin in Celsius ?
ss7ja [257]

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42.85 Celsius

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Element X is more reactive than lithium and magnesium but less reactive than potassium. Which element is most likely to be X?
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57. A recipe for s'mores calls for 2 graham crackers, 2 chocolate pieces and 1 marshmallow. If I
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Answer:Noble gases:

 are highly reactive.

 react only with other gases.

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2 years ago
Convert the following into balanced equations. ( Use the lowest possible coefficents)?(a) When gallium metal is heated in oxygen
ehidna [41]

Answer:

Explanation:

(a) Balanced reaction of gallium with oxygen is as follows:

4Ga(s)+3O_2(g) \rightarrow 2Ga_2O_3 (s)

(b) C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+H_2O(l)

Multiply the carbon dioxide by 6 to balance carbon as follows:

C_6H_{14}(l)+O_2(g)\rightarrow 6CO_2(g)+H_2O(l)

After that multiply H2O by 7 to balance hydrogen as follows:

C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+7H_2O(l)

Finally balance oxygen by multiplying O2 by 19/2. Therefore, balanced reaction is as follows:

C_6H_{14}(l)+\frac{19}{2} O_2(g)\rightarrow 6CO_2(g)+7H_2O(l)

(c) Na_3PO_4(s)+CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

first balance calcium, by multiply CaCl_2 by 3 as follows:

Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

After that balance phosphorous by multiplying Na_3PO_4 by 2 as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

Finally balance Na by multiplying NaCl by 6. Therefore, balance reaction is as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+6NaCl

3 0
3 years ago
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