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dedylja [7]
3 years ago
9

Convert the following into balanced equations. ( Use the lowest possible coefficents)?(a) When gallium metal is heated in oxygen

gas, it melts and forms solid gallium(III) oxide. (b) Liquid hexane burns in oxygen gas to form carbon dioxide gas and water vapor. (c) When solutions of calcium chloride and sodium phosphate are mixed, solid calcium phosphate forms and sodium chloride remains in solution.
Chemistry
1 answer:
ehidna [41]3 years ago
3 0

Answer:

Explanation:

(a) Balanced reaction of gallium with oxygen is as follows:

4Ga(s)+3O_2(g) \rightarrow 2Ga_2O_3 (s)

(b) C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+H_2O(l)

Multiply the carbon dioxide by 6 to balance carbon as follows:

C_6H_{14}(l)+O_2(g)\rightarrow 6CO_2(g)+H_2O(l)

After that multiply H2O by 7 to balance hydrogen as follows:

C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+7H_2O(l)

Finally balance oxygen by multiplying O2 by 19/2. Therefore, balanced reaction is as follows:

C_6H_{14}(l)+\frac{19}{2} O_2(g)\rightarrow 6CO_2(g)+7H_2O(l)

(c) Na_3PO_4(s)+CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

first balance calcium, by multiply CaCl_2 by 3 as follows:

Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

After that balance phosphorous by multiplying Na_3PO_4 by 2 as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

Finally balance Na by multiplying NaCl by 6. Therefore, balance reaction is as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+6NaCl

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A 5.098 mass % aqueous solution of potassium hydroxide has a density of 1.05 g/mL. Calculate the molality of the solution. Give
GarryVolchara [31]

<u>Answer:</u> The molarity of solution is 0.954 M

<u>Explanation:</u>

We are given:

5.098 mass % solution of potassium hydroxide

This means that 5.098 grams of potassium hydroxide is present in 100 grams of solution

To calculate volume of a substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.05 g/mL

Mass of solution = 100 g

Putting values in above equation, we get:

1.05g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.05g/mL}=95.24mL

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of potassium hydroxide = 5.098 g

Molar mass of potassium hydroxide = 56.1 g/mol

Volume of solution = 95.24 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{5.098\times 1000}{56.1\times 95.24}\\\\\text{Molarity of solution}=0.954M

Hence, the molarity of solution is 0.954 M

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I got u

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