<span>389.88094 amu
First we look up the atomic mass of all elements contained in calcium iodate using the periodic table:
Ca: 40.078
I: 126.90447
O: 15.999
As an intermediate step we calculate the molecular mass of the ion IO3:
126.90447 + 3*15.999 = 174.90147
Then we calculate the mass of one calcium atom and 2 iodate ions:
2*174.90147 + 40.078 = 389.88094 amu</span>
Mass of Na2SO4= 514.18 grams
<h3>Further explanation</h3>
Given
423.67 g of NaCl
Required
mass of Na2SO4
Solution
Reaction
2NaCl + H2SO4 → Na2SO4 + 2HCl
mol NaCl :
= 423.67 g : 58.5 g/mol
= 7.24
From the equation, mol Na2SO4 :
= 1/2 x mol NaCl
= 1/2 x 7.24
= 3.62
Mass Na2SO4 :
= 3.62 mol x 142,04 g/mol
= 514.18 grams
Answer:
The solution to the given problem is done below.
Explanation:
a)
i) =( 0.002 μg / L )( 1mg / 1000 μg )( 1L / kg )( 1000 mil / 1 billion) = 0.002 ppb
ii) =( 0.002 μg / L )( 1mg / 1000 μg )( 1L / kg )( 1,000,000 mil / 1 trillion) = 2 ppt
iii) =( 0.002 μg / L )( 1 mole / 540g ) = 3.7 x 
μM.
b)
i) =( 0.002 μg / g ) = 0.002 ppm
ii) In solids, ppb = μg/kg
=( 0.002 μg / g )( 1000 mil/ 1 billion) = 2 ppb
Explanation:
when acid reacts with water it form salt and water this reaction is called neutralization reaction
Well a mixture is less permanent and also it can be easily taken aprt where a compound does the opposite of those things.
Hope I helped :)
