I do not understand your question, what is the question, name what??
3.124mg of I-131 is present after 32.4 days.
The 131 I isotope emits radiation and particles and has an 8-day half-life. Orally administered, it concentrates in the thyroid, where the thyroid gland is destroyed by the particles.
What is Half life?
The time required for half of something to undergo a process: such as. a : the time required for half of the atoms of a radioactive substance to become disintegrated.
Half of the iodine-131 will still be present after 8.1 days.
The amount of iodine-131 will again be halved after 8.1 additional days, for a total of 8.1+8.1=16.2 days, reaching (1/2)(1/2)=1/4 of the initial amount.
The quantity of iodine-131 will again be halved after 8.1 more days, for a total of 16.2+8.1+8.1=32.4 days, to (1/4)(1/2)(1/2)=1/16 of the initial quantity.
If the original dose of iodine-131 was 50mg, the residual dose will be (50mg)*(1/16)=3.124mg after 32.4 days.
Learn more about the Half life of radioactie element with the help of the given link:
brainly.com/question/27891343
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Neutralization reaction is the reaction that occur between acid and base.
<h3>What is Neutralization reaction?</h3>
Neutralization reaction is the reaction that take place between acid and base to produce salt and water. For examples HCl react with NaOH to produce NaCl and H2O
Therefore, Neutralization reaction is the reaction between acid and base.
The question is not complete but the option are gotten from another website.
Here are the options.
- an acid and a base
- a fuel and oxygen
- an acid and a metal
- a salt and a base
Learn more about neutralization from the link below.
brainly.com/question/4090568
I actually don’t know but good question