The electronic configuration of Na is_________.
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A 29.4 ml sample of 0.347 m triethylamine, (c2h5)3n, is titrated with 0.375 m hydrobromic acid. at the equivalence point, the pH is 5.81.
Given,
Volume of Triethylamine (C₂H₅)₃N = 29.4 ml = 0.0294 L
Molarity of (C₂H₅)₃N = 0.275 M
Molarity of HBr = 0.375M
Solution:
(C₂H₅)₃N + HBr ⇔ (C₂H₅)₃ NH⁺ + Br⁻
⇒ Volume of HBr = mole of (C₂H₅)₃N / Molarity of HBr
⇒ Volume of HBr = 0.00572 mol / 0.375 mol/l
⇒ Volume of HBr = 0.0152 L
∴ Total Volume = 0.0294 + 0.0152
⇒ Total Volume = 0.0446 L
Concentration of (C₂H₅)₃NH⁺ = ⇒ 0.128 M,
(C₂H₅)₃NH⁺ + H₃O⁺ ⇄ (C₂H₅)₃N + H₃O⁺
let's assume, (C₂H₅)₃N = ,
⇒ H₃O⁺ = , and
⇒ (C₂H₅)₃NH⁺ = 0.128 -
∴ Now, k = kw / kb
⇒ k = 1.9 × 10⁻¹¹
and, k = [(C₂H₅)₃N][H₃O⁺] / (C₂H₅)₃NH⁺
⇒ 1.9 × 10⁻¹¹ = / (0.128 -
)
Thus, = 1.55 × 10⁻⁶ M,
Hence, pH = - log[x]
⇒ - log [1.55 × 10⁻⁶ ]
⇒ - log (1.55) - log (10⁻⁶)
⇒ - log (1.55) + 6log10
⇒ - 0.19 + 6
⇒ 5.81 = pH
Therefore, pH = 5.81.
To learn more about equivalence point here
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<u>Answer:</u> The balanced chemical equation for the decomposition of nitroglycerin is written below.
<u>Explanation:</u>
Decomposition reaction is defined as the reaction in which a single large substance breaks down into two or more smaller substances.
Every balanced chemical equation follows law of conservation of mass.
A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.
The balanced chemical equation for the decomposition of nitroglycerin follows:
By Stoichiometry of the reaction:
1 mole of liquid nitroglycerin decomposes into 12 moles of carbon dioxide gas, 10 moles of gaseous water, 6 moles of dinitrogen gas and 1 mole of dioxygen gas.
Hence, the balanced chemical equation for the decomposition of nitroglycerin is written above.