1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vovangra [49]
3 years ago
12

What is the maximum pressure at which solid CO2 (dry ice) can be converted into CO2 gas without melting?

Chemistry
1 answer:
max2010maxim [7]3 years ago
3 0

Answer:

Explanation:

The triple point of carbon dioxide is 5.11 atmosphere at -56.6 degree celsius . At pressure greater than 5.11 , solid carbon dioxide liquefies ,  as it is warmed. At pressure lesser than 5.11 atmosphere , it will go into gaseous state without liquefying . Excessive pressure helps liquification process.

So maximum pressure required is 5.11 atmosphere. Beyond this pressure , solid CO2 will liquify.

You might be interested in
How many Cl atoms are in Zn(ClO3)2?<br> O A. 2<br> O B. 1<br> O c. 3<br> O D. 6
White raven [17]
The answer cl atoms are in zn(cio3)2 is A:2 because I looked it up and it gave me 2.
3 0
3 years ago
Calcium carbonate and copper sulfate are each mixed into a beaker of water.
Natalka [10]
The correct answer is C: Calcium carbonate in water is a solution
8 0
2 years ago
Someone who’s good with science this is for you btw I’ll brainlist and rate 5 star due today.
alekssr [168]

Answer:

Solid Osmium transition metal reacts with Oxygen gas to produce solid Osmium tetroxide.

Os(s) + 2O₂(g) -> OsO₄(s)

Explanation:

Osmium tetroxide is another way of writing Osmium (VIII) oxide.

Leaving powdered osmium exposed to air in a room will slowly create osmium tetroxide at room temperature.

Similarly, osmium tetroxide vapor will readily be released from a liquid solution at room temperature.

7 0
2 years ago
A student ran the following reaction in the laboratory at 671 K: 2NH3(g) N2(g) + 3H2(g) When she introduced 7.33×10-2 moles of N
vaieri [72.5K]

Answer:

Kc = 8.05x10⁻³

Explanation:

This is the equilibrium:

                 2NH₃(g)   ⇄     N₂(g)     +     3H₂(g)

Initially       0.0733

React         0.0733α          α/2                3/2α

Eq     0.0733 - 0.0733α    α/2                0.103

We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.

Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.

3/2α = 0.103

α = 0.103 . 2/3 ⇒ 0.0686

So, concentration in equilibrium are

NH₃ = 0.0733 - 0.0733 . 0.0686 = 0.0682

N₂ = 0.0686/2 = 0.0343

So this moles, are in a volume of 1L, so they are molar concentrations.

Let's make Kc expression:

Kc= [N₂] . [H₂]³ / [NH₃]²

Kc = 0.0343 . 0.103³ / 0.0682² = 8.05x10⁻³

3 0
3 years ago
Which is one way that scientist communicate the result of an experiment
arlik [135]

Answer:

wove oral visalize  

Explanation:

7 0
3 years ago
Other questions:
  • The proprietor of a rock shop insists that a nugget is pure gold. if the nugget occupies a volume of 5.40 ml, what would its mas
    12·1 answer
  • LAST QUESTION HELPPPP!!!!
    15·2 answers
  • How many moles of ethylene can react with 12.9 l of oxygen gas at 1.2 atm in 297 k
    13·1 answer
  • When U-238 undergoes radioactive decay by losing an alpha particle, the other product is
    9·2 answers
  • Your science teacher gives you three liquids to pour into a jar. After pouring, the liquids layer as seen here. What property of
    8·2 answers
  • A student has two solutions of a substance;Solution-1:25M , 400ml and Solution-2:30M , 300M. What is the molarity of the final s
    14·1 answer
  • Explain the processes involved in storing information in a scientific workplace
    10·1 answer
  • What is the product of the unbalanced combustion reaction below?
    5·1 answer
  • How are air resistance and friction similar?
    8·2 answers
  • [H3O+] = 2.9 x 10-10 M<br> ph level
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!