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2 years ago

13

Using a schematic diagram, explain the steps of the laser technique.

1 answer:

nignag [31]2 years ago

3 0

The steps of the use of the laser technique is explained below:

A laser beam is emitted from the diode in the unit and spread into a laser plane (1).
The laser plane, appearing as a line on the sphere (2), is reflected and collected by dual CCD arrays (1).
The resulting 2D profile is digitized and as the unit travels along the x-axis of the object, multiple profiles are collected yielding a 3D coordinate point cloud of the surface (3).

<h3>What is a Laser Technique?</h3>

This refers to the type of surgery that makes use of special light beams in order to cut open the human body in a surgical procedure.

Hence, we can see that the laser technique is considered safer than conventional surgical methods.

Laser techniques include:

laser vaporization,
laser resection-enucleation,
coagulation.

Read more about laser technique here:

brainly.com/question/14091177

#SPJ1

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The velocity of an object includes its speed and____?

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3 years ago

Find the velocity of a baseball thrown 78 m from third base to first base in 30 sec

ankoles [38]

Answer:

V=2.6m/s

Explanation:

velocity=Distance/time

V=78/30=2.6m/s

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3 years ago

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MrRissso [65]

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3 years ago

(a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32º ramp at a speed

stiks02 [169]

a) 7 buses

b) 6.8 m

Explanation:

a)

The motion of the motorcycle is a projectile motion, so it consists of 2 independent motions:

- A uniform motion along the horizontal direction

- A uniformly accelerated motion along the vertical direction

The initial components of the velocity of the motorcycle are:

$v_x = u cos(32^{\circ})=(40.0)(cos 32^{\circ})=33.9 m/s\\v_y = u sin(32^{\circ})=(40.0)(sin 32^{\circ})=21.2 m/s$

The equation for the vertical motion of the motorcycle is

$y=h+u_y t - \frac{1}{2}gt^2$

where

y is the altitude at time t

h is the initial height

$g=9.8 m/s^2$ is the acceleration due to gravity

The bus top is at the same height of the initial ramp, so we have

$y=h$

And therefore, we can solve the equation for t, to find the time of flight:

$0=u_y t - \frac{1}{2}gt^2\\t(u_y-\frac{1}{2}gt)=0\\t=\frac{2u_y}{g}=\frac{2(21.2)}{9.8}=4.33 s$

Now we find what is the horizontal distance covered by the motorcycle in its jump, which is given by:

$d=v_x t = (33.9)(4.33)=146.8 m$

And since each bus has a length of L = 20.0 m, the number of buses that the motorcycle can clear with its jump is:

$n=\frac{d}{L}=\frac{146.8}{20}=7.34$

So, 7 buses.

b)

In the previous problem, we saw that the total range of the motion of the motorcycle is

$d=146.8 m$

And we said that this corresponds to 7 buses.

Each bus has a length of

L = 20 m

So, the total length of 7 buses is

$L' = 7L=7(20)=140 m$

Therefore, the range of the motorcycle is greater than the length of the buses by:

$\Delta x = d-L'=146.8-140 = 6.8 m$

which means he will miss the last bus by 6.8 meters.

6 0

3 years ago