Explanation :
Displacement refers to the distance between the final and the initial position. Hence the displacement of the ball will be the difference between the initial and the final displacement.
Let the initial position be 0.
Final position = 8 cm
So the difference between initial position and final position = 0 – 8 = - 8 cm.
So the billiard ball comes to rest 8.0 cm behind its orbital position.
In collision of the steel ball and the steel plate, the collision is an inelastic collision and there is loss in the kinetic energy.
<h3>What are collisions?</h3>
Collisions occur when two objects that are moving in the same directions or in different direction meet each other and collide.
There are two types of collisions:
- elastic collision - the kinetic energy is conserved
- inelastic collision - there is a loss in kinetic energy
In the collision of the steel ball and the steel plate, there is loss in the kinetic energy of the steel ball which is converted to sound energy.
In conclusion, the collision of the steel and steel plate is an inelastic collision.
Learn more about collisions at: brainly.com/question/7694106
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The angular momentum is defined as,

Acording to this text we know for conservation of angular momentum that

Where
is initial momentum
is the final momentum
How there is a difference between the stick mass and the bug mass, we define that
Mass of the bug= m
Mass of the stick=10m
At the point 0 we have that,

Where l is the lenght of the stick which is also the perpendicular distance of the bug's velocity
vector from the point of reference (O), and ve is the velocity
At the end with the collition we have

Substituting




Applying conservative energy equation we have


Replacing the values and solving

Substituting
l=\frac{13}{0.54(9.8)}

Answer:
The blade of sharpener is made up of iron. Iron is a magnetic material because of this pencil sharpener gets attracted by the poles of a magnet although the body is made up of plastic.
Answer:
0.358g
Explanation:
Density of Helium = 0.179g/L
ρ=m/v
m=ρv
when the volume was 2L
m1= 0.179*2
m1=0.358g
when the volume increased to 4L
m2= 0.179*4
m2=0.716g
gram of helium added = 0.716g-0.358g
=0.358g