Answer:
Explanation:
Let electric potential at A ,B and C be Va , Vb and Vc respectively.
Work done = charge x potential difference
Wab = q ( Va - Vb )
Wac = q ( Va - Vc )
Given
Wac = - Wab / 3
3Wac = - Wab
Now
Wbc = q ( Vb - Vc )
= q [ ( Va-Vc ) - ( Va - Vb )]
= Wac - Wab
= Wac + 3Wac
= 4Wac
The parallel component is given by
F=180cos(25)=163.14N
Solve for "x"
X=force
18/6=x/9
cross multiply
162=6x
x=27
Hope this helps
Answer:
pahingi po ng pic pls para masagutang kopo iyan