The Young modulus E is given by:

where
F is the force applied
A is the cross-sectional area perpendicular to the force applied

is the initial length of the object

is the increase (or decrease) in length of the object.
In our problem,

is the initial length of the column,

is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:

and the cross-sectional area is

The force applied to the column is the weight of the load:

Now we have everything to calculate the compression of the column:

So, the column compresses by 1.83 millimeters.
Answer:
0 m/s
Explanation:
Velocity is displacement over time. Displacement is the distance between your initial position and your final position. If you walk in a circle, you end up back where you started, so your displacement is 0. Therefore, your velocity is also 0.
Answer: certificate authority
Explanation: The user submits Identification data and certificate request to the registration authority (RA). The RA validates this information and sends the certificate request to the certificate Authority (CA)
The statement which is true about a piece of ice at 0°C which is put into a freezer at -18°C is it having the temperature of the freezer.
<h3>What is Temperature?</h3>
This is referred to the degree of hotness or coldness of a body and the unit is Celsius or Kelvin.
The ice at 0°C will experience a change in temperature of the freezer when put in it in this scenario.
Read more about Ice here brainly.com/question/2267329
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Answer:Consider a rechargeable lithium cell that is to be used to power a camcorder. Construct a problem in which you calculate the internal resistance of the cell during normal operation. Also, calculate the minimum voltage output of a battery charger to be used to recharge your lithium cell. Among the things to be considered are the emf and useful terminal voltage of a lithium cell and the current it should be able to supply to a camcorder.
Explanation: