All categories

3 years ago

Which type of energy is the original source for the energy that food molecules can provide?

Physics

1 answer:

Svet_ta [14]3 years ago

4 0

Answer:

Chemical potential energy

Explanation:

which is used to for any form of energy.

You might be interested in

He power output of a cyclist moving at a constant speed of 5.3 m/s on a level road is 120 w. (a) what is the force exerted on th

EleoNora [17]

P=F*V
F=P/V
F=120/5.3
F=22.6N

8 0

3 years ago

A5 cm object is 18.0 cm from a convex lens, which has a focal length of 10.0 cm.

Masja [62]

Explanation:

We have,

Height of object is 5 cm

Object distance from a convex lens is 18 cm

Focal length of convex lens is 10 cm

i.e. h = 5 cm

u = -18 cm

f = +10 cm

Let v is distance of the image from the lens. Using lens formula :

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{(-18)}\\\\v=22.5\ cm$

The magnification of lens is :

$m=\dfrac{v}{u}=\dfrac{h'}{h}$ , h' is height of the image

$\dfrac{v}{u}=\dfrac{h'}{h}\\\\h'=\dfrac{vh}{u}\\\\h'=\dfrac{22.5\times 4}{(-18)}\\\\h'=-5\ cm$

h' = -5.00 cm (in three significant figures)

6 0

3 years ago

Is erosion a constructive or destructive force and why?

Andrei [34K]

Destructive force
It’s a force that slowly wears away mountains and other features on earths surface, such as erosion.

5 0

3 years ago

A planet orbits a star, in a year of length 2.27 x 107 s, in a nearly circular orbit of radius 3.99 x 1011 m. With respect to th

luda_lava [24]

Explanation:

It is given that,

Radius of circular orbit, $r=3.99\times 10^{11}\ m$

Time taken, $t=2.27\times 10^{7}\ m$

(a) Angular speed of the planet is given by :

$\omega=\dfrac{2\pi}{t}$

$\omega=\dfrac{2\pi}{2.27\times 10^{7}\ m}$

$\omega=2.76\times 10^{-7}\ rad/s$

(b) The tangential speed of the planet is given by :

$v=r\times \omega$

$v=3.99\times 10^{11}\times 2.76\times 10^{-7}$

v = 110124 m/s

(c) The centripetal acceleration of the planet,

$a=\dfrac{v^2}{r}$

$a=\dfrac{(110124)^2}{3.99\times 10^{11}}$

$a=0.0303\ m/s^2$

Hence, this is the required solution.

3 0

3 years ago

A rescue helicopter is hovering over a person whose boat has sunk. one of the rescuers throws a life preserver straight down to

Helga [31]

When the life preserver is dropped from the helicopter, the only force acting on the object is the gravitational force. This modifies the equations of motion. Thus, the working equation is written below:

h = vt + 0.5gt²
where
v is the initial velocity
g is the acceleration due to gravity equal to 9.81 m/s²
h is the height of the fall

h = (1.46 m/s)(1.8 s) + 0.5(9.81 m/s²)(1.8 s)
h = 11.457 m

7 0

3 years ago