I would typically assume it is error in the state (s, l, g, aq) but depending on what reaction i couldn't say for sure
Answer:
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To calculate the numbers of subatomic particles in an atom, use its atomic number and mass number:
number of protons = atomic number.
number of electrons = atomic number.
number of neutrons = mass number - atomic number.
Explanation:
<u>Answer:</u> In heterogeneous mixture, the composition remains variable throughout.
<u>Explanation:</u>
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Homogeneous mixtures are defined as the mixtures that appears uniformly throughout the solution and the particle size or shapes are not different. The composition remains constant throughout.
A solution is defined as the solution in which the components gets completely dissolved in it. Particles are evenly spread in these solutions. These solution does not scatter light falling on it. The composition remains constant throughout.
An amorphous solid is defined as the solid in which the constituent particles of the matter are arranged in the random manner. The composition remains constant throughout.
A heterogeneous mixture is defined as the mixture in which component are unevenly spread throughout the solution. The size and shape of the particles differ in these mixtures. These mixture scatter the light falling on it. The composition do not remains constant throughout.
Compound is defined as the chemical specie which is formed by the combination of two or more different type of atoms. <u>For Example:</u> etc...The composition remains constant throughout.
Hence, in heterogeneous mixture, the composition remains variable throughout.
Answer:
After complete reaction, 0.280 moles of ammonia are produced
Explanation:
Step 1: Data given
Number of moles N2 = 0.140 moles
Number of moles H2 = 0.434 moles
Step 2: The balanced equation
N2(g) + 3H2 (g) ⟶ 2NH3 (g)
Step 3: Calculate the limiting reactant
For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3
N2 is the limiting reactant. It will completely be consumed (0.140 moles).
H2 is in excess. There will react 3*0.140 = 0.420 moles
There will remain 0.434 - 0.420 = 0.014 moles
Step 4: Calculate moles NH3
For 0.140 moles N2 we'll have 2*0.140 = 0.280 moles NH3
After complete reaction, 0.280 moles of ammonia are produced