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Tcecarenko [31]

3 years ago

5

This same pot of water initially started with 100ml and a temperature of 280 C. The water temperature rose to 1030 C. How much e

nergy was absorbed by the water? (Specific heat of water is 1) q=mCΔT

1 answer:

Harlamova29_29 [7]3 years ago

3 0

Answer:The temperature change is 80°C

Explanation:

Heat absorbed by the melting ice (Q) = mL = 312×336 = 104,832 J

∆T = Q/mC = 104,832/312×4.2 = 80°C

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