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RUDIKE [14]
3 years ago
14

Describe the process of evaporation condensation, and precipitation

Chemistry
2 answers:
murzikaleks [220]3 years ago
8 0

Answer:

Evaporation is a type of vaporization that occurs on the surface of a liquid as it changes into the gas phase. Precipitation is water released from clouds in the form of rain, freezing rain, sleet, snow, or hail. Condensation is the process by which water vapor in the air is changed into liquid water.

Explanation:

sukhopar [10]3 years ago
4 0

Answer:

  1. eva... water to gaseous foum .... condensation liquid to solid and perp ..... water that is falling out of the sky, this could be rain, drizzle, snow, sleet, hail or something rarer!
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The main buffering agents in human blood are h2co3 and hco3. Explain how this buffering system will be able to maintain blood pH
den301095 [7]

Answer:

The base, HCO₃⁻ of the buffering system will neutralize the acid added forming H₂CO₃.

Explanation:

A buffer solution keeps the pH in a narrow range upon the addition of an acid or base. A buffer consists of a pair of a weak acid and its conjugate base, or vice versa, in a pair of a weak base and its conjugate acid. In the case of human blood, the acid is H₂CO₃ and its conjugate base is HCO₃⁻.

The buffering system of the human blood maintain blood pH at a steady level when a small amount of a generic acid HA is added in the following way:

HCO₃⁻ + HA  ⇄  H₂CO₃ + A⁻

The base, HCO₃⁻, will neutralize the acid added forming the H₂CO₃, which is already a component of the buffering system of the human blood. Thus, hydronium ions of the acid added are removed, preventing the pH of blood from becoming acidic.                

On the other hand, when a small amount of a generic base A⁻ is added the following reaction takes place:    

H₂CO₃ + A⁻  ⇄  HCO₃⁻ + HA

In this case, the acid H₂CO₃ will neutralize the base added to form the base HCO₃⁻, which is already a component of the buffering system. Thus, the base added are removed from the blood, preventing the pH of blood from becoming basic.  

Since, the acid or its conjugate base will react with the base or acid added, to neutralizing it and forming the species that conform the buffer solution, the pH is being maintained at a steady level.  

In the process above, the addition of a small amount of an acid or a base won't change in a significant way the concentrations of the two components of the buffering system. This buffering mechanism prevents the blood from becoming acidic or basic.  

                   

I hope it helps you!

6 0
3 years ago
In the Lab you report a measured volume 128.7 of water. Using significant figures as a measure, what range of answers does your
Cerrena [4.2K]

Your measurement implies that the range of answers is 128.6 mL to 128.8 mL.

If you do not state explicitly the range of uncertainty (e.g., ± 0.5 mL), the <em>implied range of uncertainty</em> is ±1 in the last significant digit.

Thus, a reading of 128.7 mL implies that the volume is 128.7 mL ± 0.1 mL.

7 0
3 years ago
The reaction of methane with water to form carbon dioxide and hydrogen is nonspontaneous at 298 K. At what temperature will this
KIM [24]

Answer:

The system makes the transition from nonspontaneous to spontaneous at a temperature of 954.7 K.

Under 954.7 K the reaction is nonspontaneous; more than 954.7 K is the reaction spontaneous.

Explanation:

CH4(g) + 2H2O(g) ⇆ CO2(g) + 4H2(g)

CH4(g) H2O(g) CO2(g) H2(g) ΔH°f (kJ/mol): –74.87 –241.8 –393.5 0

ΔG°f (kJ/mol): –50.81 –228.6 –394.4 0

S°(J/K·mol): 186.1 188.8 213.7 130.7

ΔG<0 to be spontaneous

ΔG = ΔH- TΔS <0

ΔH = ∑nΔH(products) - ∑nΔH(reactant)

ΔH = (-393.5) - (–74.87 + 2*–241.8)

ΔH = 164.97 kJ = 164970 J

ΔS = ∑nΔS(products) - ∑nΔS(reactant)

ΔS = (213.7 + 4*130.7) - (186.1 + 2*188.8)

ΔS = 172.8 J

0 > 164970 J - T* 172.8 J

-164970 J > - T* 172.8 J

954.7< T

The system makes the transition from nonspontaneous to spontaneous at a temperature of 954.7 K.

Under 954.7 K the reaction is nonspontaneous; more than 954.7 K is the reaction spontaneous.

8 0
3 years ago
How many moles of aluminum nitrate can be produced with 0.68 moles of lead nitrate?​
Brrunno [24]

i have no idea  can somebody help me too

6 0
3 years ago
What is the energy of light with a wavelength of 468 nm? (The speed of light
marshall27 [118]

The answer for the problem is explained below.

The option for the answer is "D".

<u><em>Therefore the energy of the light is  4.25 × 10^-19 J</em></u>

Explanation:

Given:

wavelength (λ) = 468 nm = 468×10^-9 m

speed of light (c) = 3.00 x 10^8m/s

Planck's constant is 6.626 x 10^-34J·s

To solve:

energy of light (E)

We know,

E =(h×c) ÷ λ

E = ( 6.626 x 10^-34 ×  3.00 x 10^8) ÷ 468×10^-9

E = 4.25 × 10^-19 J

<u><em>Therefore the energy of the light is  4.25 × 10^-19 J</em></u>

6 0
2 years ago
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