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Margaret [11]
3 years ago
10

How many grams is 2.25mol.of methane (CH)?

Chemistry
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:  16.04246 grams

Explanation:

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For the following questions, name the ionic compound using a periodic table and the polyatomic ion chart. Be sure to use correct
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Sodium Flouride
Magnesium Nitrate
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Sodium Oxide
Lead Iodide
Copper Sulphate

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3 years ago
BRAINLIEST IF YOU GET IT!! 5 STARS & A THANK YOU!!
Keith_Richards [23]

Answer:

B.

Explanation:

Minerals are formed due to chemical composition by rocks are pressured into their formed from dirt and naturally hard things.

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3 years ago
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Hatshy [7]
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7 0
4 years ago
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What would the percentage of thorium-232 (parent compound) be in a rock that was dated at 2.8 billions years?
just olya [345]

The half-life of Th-232 is 1.405 × 10¹⁰ years  

Time elapsed = 2.8 x 10⁹ years  

Equation of radioactive decay:

A = A₀ = (1/2)^ t/t₁/₂

where A₀ is the initial amount, A is the amount after time t, t₁/₂ is the half file

The fraction of thorium-232 that remains in the rock after 2.8 billions years is,

A/A₀ = (1/2) ^ (2.8 x 10⁹/ 1.405 × 10¹⁰) = 0.871

Therefore, the percentage of thorium-232 in the rock that was dated at 2.8 billions year = 87.1%


5 0
4 years ago
1.25mole Nocl was placed in a2.50l reaction chamber at 427c. After equilibrium was reached .1.10moles of Nocl remained.Calculate
Dmitry [639]

Answer:

Kc → 5.58×10⁻⁴

Explanation:

Equilibrium reaction is:

2NOCl (g) ⇄  2NO (g) + Cl₂(g)

Initially we have 1.25 moles of NOCl

After the equilibrium, we have 1.10 moles. So, during the process:

(1.25 mol - 1.1 mol) = 0.15 moles have reacted.

As ratio are 2:2, and 2:1, 0.15 moles of NO and (0.15 /2) = 0.075 moles of chlorine, were produced in the equilibrium.

Finally in equilibrium we have: 1.10 moles of NOCl, 0.15 moles of NO and 0.075 moles of Cl₂. But these amount are not molar, so we need molar concentration in order to determine Kc:

1.10 mol /2.50L = 0.44 M

0.15 mol / /2.50L = 0.06 M

0.075 mol /2.50L = 0.03 M

Let's make expression for Kc → [Cl₂] . [NO]² / [NOCl]²

Kc = (0.03 . 0.06²) / 0.44² → 5.58×10⁻⁴

4 0
3 years ago
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