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3 years ago

Which type radiation can be observed well from Earth's surface?

Physics

2 answers:

ddd [48]3 years ago

6 0

Answer:

Gamma Ray's as they have the shortest wavelength and highest frequency in the electromagnetic Spectrum.

umka2103 [35]3 years ago

4 0

Answer:

Eletromagnetic radiation which is also known as visible light.

Explanation:

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(a) If the coefficient of kinetic friction between tires and dry pavement is 0.80, what is the shortest distance in which you ca

Colt1911 [192]

a) 52.5 m

b) 16.0 m/s

Explanation:

The motion of a car slowed down by friction is a uniformly accelerated motion, so we can use the following suvat equation:

$v^2-u^2=2as$

where

v = 0 is the final velocity (the car comes to a stop)

u = 28.7 m/s is the initial velocity of the car

a is the acceleration

s is the stopping distance

For a car acted upon the force of friction, the acceleration is given by the ratio between the force of friction and the mass of the car, so:

$a=\frac{-\mu mg}{m}=-\mu g$

where:

$\mu=0.80$ is the coefficient of friction

$g=9.8 m/s^2$ is the acceleration due to gravity

Substituting and solving for s, we find:

$s=\frac{v^2-u^2}{-2\mu g}=\frac{0-(28.7)^2}{-2(0.80)(9.8)}=52.5 m$

In this case, the car is moving on a wet road. Therefore, the coefficient of kinetic friction is

$\mu=0.25$

Here we want the stopping distance of the car to remain the same as part a), so

$s=52.5 m$

We can use again the same suvat equation:

$v^2-u^2=2as$

And since the final velocity is zero

u = 0

We can find the initial velocity of the car:

$v=\sqrt{2as}=\sqrt{2\mu gs}=\sqrt{2(0.25)(9.8)(52.5)}=16.0 m/s$

7 0

3 years ago

Pls answer quick & an accurate answer will get brainliest

Oliga [24]

Answer:

3.766 kg or 3.7 kg

Explanation:

F= M*A equation

6 0

3 years ago

A 2 kg body is dropped from a height of 3 m. Calculate:

NikAS [45]

Answer:

a) 6.26 m/s

b) 7.67 m/s

Explanation:

The potential energy at height h0 is initially ...

PE0 = mgh0

At height h1, the potential energy is ...

PE1 = mgh1

The difference in potential energy is converted to kinetic energy:

PE0 -PE1 = KE1 = (1/2)m(v1)^2

Solving for v1, we have ...

mg(h0 -h1) = (1/2)m(v1)^2

2g(h0 -h1) = (v1)^2

v1 = √(2g(h0 -h1))

a) When the body is 1 m high, its speed is ...

v = √(2(9.8)(3 -1)) ≈ 6.26 m/s . . . at 1 m high

b) When the body is 0 m high, its speed is ...

v = √(2(9.8)(3 -0)) ≈ 7.67 m/s . . . when it reaches the ground

3 0

3 years ago

Plz answer the question

Vikentia [17]

Answer:

Ray A = Incidence ray

Ray B = Reflected ray

Explanation:

From the law of reflection,

Normal: This is the line that makes an angle of 90° with the reflecting surface.

Ray A is the incidence ray: This is the ray that srikes the surface of a reflecting surface. The angle formed between the normal and the incidence ray is called the incidence angle

Ray B is the reflected ray: This is the ray leaves the surface of a reflecting surface. The angle formed between the reflected ray and the normal is called reflected angle

3 0

3 years ago

Which projectiles will be visibly affected by air resistance when they fall?

leva [86]

Answer:

Balloon, leaf

Explanation:

Objects that are light and have a relatively large surface that Is affected by the friction with air.

8 0

3 years ago