3B with worked out equations please
1 answer:
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No. of ways in the elements of n be permuted is n!/4
Number of elements = n
Number of face in which the element of n be permuted if 1 must proceed 2 and 3 is to precede 4.
n = 4
The possible permutation will
(1,2,3,4), (1,3,2,4),(1,3,4,2),(3,4,1,2),(3,1,2,4),(3,1,4,2)
There are 6 possible outcomes
For n= 5
With 1,2,3,4 we add 5 in the arrangement with above terms
The possible number of permutation
5×6 = 30
When n = 6
30×6 = 180.
So for an element
If 1 precede 2 and 3 is yo precede 4 is
<h2>= n! ×6/4!
= n!/4
No. of ways in the elements of n be permuted is n!/4
To know more about permutation:
#SPJ4
Answer:
(A)
(B)
Explanation:
We have given inductance
Resistance
Time constant of RL circuit is equal to
Battery voltage e = 16 volt
(a) It is given current becomes 79.9% of its final value
Current in RL circuit is given by
According to question
(b) Current at
Answer:
T₂ = 123.9 N, θ = 66.2º
Explanation:
To solve this exercise we use the law of equilibrium, since the diaphragm does not appear, let's use the adjoint to see the forces in the system.
The tension T1 = 100 N, we create a reference frame centered on the pole
X axis
T₁ₓ - = 0
T_{2x}= T₁ₓ
Y axis y
T_{1y} + T_{2y} - 200N = 0
T_{2y} = 200 -T_{1y}
let's use trigonometry to find the component of the stresses
sin 60 = T_{1y} / T₁
cos 60 = t₁ₓ / T₁
T_{1y} = T₁ sin 60
T1x = T₁ cos 60
T_{1y}y = 100 sin 60 = 86.6 N
T₁ₓ = 100 cos 60 = 50 N
for voltage 2 it is done in the same way
T_{2y} = T₂ sin θ
T₂ₓ = T₂ cos θ
we substitute
T₂ sin θ= 200 - 86.6 = 113.4
T₂ cos θ = 50 (1)
to solve the system we divide the two equations
tan θ = 113.4 / 50
θ = tan⁻¹ 2,268
θ = 66.2º
we caption in equation 1
T₂ cos 66.2 = 50
T₂ = 50 / cos 66.2
T₂ = 123.9 N
