1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
dezoksy [38]
3 years ago
11

Increase the accurancy of a scientific experiment

Physics
2 answers:
ArbitrLikvidat [17]3 years ago
7 0
The best way to increase the accuracy of a scientific experiment is to have a detailed plan of action for conducting the experiment. You should also repeat the experiment several times to ensure that you get the same result(s) consistently.<span />
Charra [1.4K]3 years ago
3 0
Have an idea them make it detailed then do it having correct measurements
You might be interested in
Helpppppppp<br> ill give brainliest
Nina [5.8K]

Answer:

I believe the answer is

B. \: 3 \: red, \: 8 \: yellow, \: 1 \: blue

Explanation:

I may be incorrect because I used to do this a long time ago but I believe I am correct

HOPE THIS HELPS!

(:

4 0
3 years ago
13. What bone runs parallel to the fibula?<br> A. Radius<br> B. Femur<br> C. Tibia<br> D. Ulna
Paraphin [41]

Answer:

C, Tibia.

  • The tibia is located down in the lower leg. Heres what it looks like.

i hope this helped at all.

8 0
3 years ago
Read 2 more answers
The sum of two component vectors is referred to as the
blondinia [14]
Resultant is the correct answer!
8 0
3 years ago
25 POINTS
Alexandra [31]

pshyical change is a usually reversible change of a substance, as size or shape: Freezing a liquid is a physical change. Compare chemical change.

internal change is when the movement of the particles increases

specific latent heat is the amount of energy per kg (unit mass) required to change ice to water without change in temperature.

4 0
3 years ago
Read 2 more answers
Using Gauss's law, calculate the electric field at a point distance s from a long wire bearing uniform charge density. i need he
11111nata11111 [884]

Answer:

E = 2k  \frac{\lambda}{ r}

Explanation:

Gauss's law states that the electric flux equals the wax charge between the dielectric permeability.

We must define a Gaussian surface that takes advantage of the symmetry of the problem, let's use a cylinder with the faces perpendicular to the line of charge. Therefore the angle between the cylinder side area has the same direction of the electric field which is radial.

            Ф = ∫ E . dA = E ∫ dA = q_{int} /ε₀

tells us that the linear charge density is

            λ = q_ {int} /l

            q_ {int} = l λ

we substitute

            E A = l λ /ε₀

is area of ​​cylinder is

           A = 2π r l

we substitute

            E = \frac{ l \ \lambda}{ \epsilon_o \ 2\pi  \ r \ l }

             E = \frac{\lambda}{ 2\pi  \epsilon_o \ r}

the amount

            k = 1 / 4πε₀

            E = 2k  \frac{\lambda}{ r}

5 0
3 years ago
Other questions:
  • Calculate the gravitational potential energy of the interacting pair of the Earth and a 11 kg block sitting on the surface of th
    10·1 answer
  • A car of mass 1500 kg travels due East with a constant speed of 25.0 m/s. Eventually it turns right, and travels due South with
    7·1 answer
  • What type of device is a coal-fired power plant?
    9·1 answer
  • Have researchers have now been able to cool substances to absolute zero
    5·1 answer
  • The Minnesota Wild's Jared Spurgeon unloads a slapshot that imparts a force of 65 Newtons of a puck. What is the force that the
    15·1 answer
  • Sound travels fastest through
    9·1 answer
  • عند زيادة تردد الدينامو . فماذا يحدث لشده التيار المار بالدائرة ​
    13·1 answer
  • What physical properties does krypton have
    13·1 answer
  • What is The force of gravity between the Aeneas and earth
    13·1 answer
  • A projectile is fired in such a way that its horizontal range is equal to three times its maximum height. What is the angle of p
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!