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dezoksy [38]
3 years ago
11

Increase the accurancy of a scientific experiment

Physics
2 answers:
ArbitrLikvidat [17]3 years ago
7 0
The best way to increase the accuracy of a scientific experiment is to have a detailed plan of action for conducting the experiment. You should also repeat the experiment several times to ensure that you get the same result(s) consistently.<span />
Charra [1.4K]3 years ago
3 0
Have an idea them make it detailed then do it having correct measurements
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Define the relationship between force acceleration and mass
goblinko [34]
Force is mass times acceleration. This means an object with a larger mass needs a stronger force to be moved along at the same acceleration as an object with a small mass
4 0
3 years ago
A particle moving along the x-axis has a position given by m, where t is measured in s. What is the magnitude of the acceleratio
8090 [49]

Question:

A particle moving along the x-axis has a position given by x=(24t - 2.0t³)m, where t is measured in s. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero

Answer:

24 m/s

Explanation:

Given:

x=(24t - 2.0t³)m

First find velocity function v(t):

v(t) = ẋ(t) = 24 - 2*3t²

v(t) = ẋ(t) = 24 - 6t²

Find the acceleration function a(t):

a(t) = Ẍ(t) = V(t) = -6*2t

a(t) = Ẍ(t) = V(t) = -12t

At acceleration = 0, take time as T in velocity function.

0 =v(T) = 24 - 6T²

Solve for T

T = \sqrt{\frac{-24}{6}} = \sqrt{-4} = -2

Substitute -2 for t in acceleration function:

a(t) = a(T) = a(-2) = -12(-2) = 24 m/s

Acceleration = 24m/s

4 0
3 years ago
A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan
mariarad [96]

Answer:

d = 9.69 cm

Explanation:

given,

mass of the block = 1.2 Kg

spring force constant(k) = 730 N/m

spring is compressed = d = ?

rough patch width = 5 cm

μ_k = 0.44

work done by friction = energy lost

\mu_k mg \times x = \dfrac{1}{2}kd^2-\dfrac{1}{2}mv^2

0.44\times 1.2 \times 9.8 \times 0.05 = \dfrac{1}{2}\times 730 \times d^2-\dfrac{1}{2}\times 1.2 \times 2.3^2

3.432 = 365 d^2

d = \dfrac{3.432}{365}

d = 0.0969 m

d = 9.69 cm

5 0
3 years ago
Please help me i need help only way i’ll pass
pickupchik [31]

Answer:

they require a medium

Explanation:

your welcome.............

3 0
2 years ago
What effect does the force from your foot have on the Earth?
Alex73 [517]
Gravitional force
It depends on your mass
3 0
2 years ago
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