Answer:
2.9 m
Explanation:
First find the time it takes to reach the floor.
y = y₀ + v₀ t + ½ at²
(0 m) = (1.6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 0.571 s
Next, find the distance it travels in that time.
x = x₀ + v₀ t + ½ at²
x = (0 m) + (5.0 m/s) (0.571 s) + ½ (0 m/s²) (0.571 s)²
x = 2.86 m
Rounded to two significant figures, the marble travels 2.9 meters in the x direction.
The same braking force does work on these objects to slow them down. The work done is equal to their change in kinetic energy:
FΔx = 0.5mv²
F = force, Δx = distance traveled, m = mass, v = speed
Isolate Δx:
Δx = 0.5mv²/F
Calculate Δx for each object.
Object 1: m = 4.0kg, v = 2.0m/s
Δx = 0.5(4.0)(2.0)²/F = 8/F
Object 2: m = 1.0kg, v = 4.0m/s
Δx = 0.5(1.0)(4.0)²/F = 8/F
The two objects travel the same distance before stopping.
Answer:
the total mass is 35 kg
k.E = 1/2 mv2
43.76 =1/2 v2
v2=2×43.76
Explanation:
v=radicls 87.52 which is equal to 9.5 m/s
<u>Answer:</u>
According to newton's first law of motion, friction is required to make an object slow down.
<u>Explanation:</u>
According to the Newton's first law of motion, for an object to change its velocity (either a change in the magnitude or the direction), there must be a cause to it which is defined as a net external force.
For example, an object which is sliding across a table or floor slows down due to the net force of friction that is acting on that object.
Answer:
Work done, W = 84.57 Joules
Explanation:
It is given that,
Mass of the wooden block, m = 2 kg
Tension force acting on the string, F = 30 N
Angle made by the block with the horizontal, 
Distance covered by the block, d = 3 m
Let W is the work done by the tension force. It can be calculated as :
W = 84.57 Joules
So, the work done by the tension force is 84.57 Joules. Hence, this is the required solution.
