Answer:
v₁ = 3.5 m/s
v₂ = 6.4 m/s
Explanation:
We have the following data:
m₁ = mass of trailing car = 400 kg
m₂ = mass of leading car = 400 kg
u₁ = initial speed of trailing car = 6.4 m/s
u₂ = initial speed of leading car = 3.5 m/s
v₁ = final speed of trailing car = ?
v₂ = final speed of leading car = ?
The final speed of the leading car is given by the following formula:
<u>v₂ = 6.4 m/s</u>
The final speed of the leading car is given by the following formula:
<u>v₁ = 3.5 m/s</u>
Answer:
The average emf that will be induced in the wire loop during the extraction process is 37.9 V
Explanation:
The average emf induced can be calculated from the formula
Where is the number of turns
is the change in magnetic flux
is the time interval
The change in magnetic flux is given by
Where is the final magnetic flux
and is the initial magnetic flux
Magnetic flux is given by the formula
Where is the magnetic field
is the area
and is the angle between the magnetic field and the area.
Initially, the magnetic field and the area are pointed in the same direction, that is,
From the question,
B = 1.5 T
and radius = 15.0 cm = 0.15 m
Since it is a circular loop of wire, the area is given by
∴
∴
( NOTE: )
Wb
For
The field pointed upwards, that is . Since
Then
Hence,
From the question
Here, = 1
Hence,
becomes
Hence, the average emf that will be induced in the wire loop during the extraction process is 37.9 V.