Answer:
i don't know but i hope you get it right
Explanation
<h2>Answers:</h2>
<h2>1. Differraction Pattern:
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The diffraction pattern is that formed when a wave is deflected when it passes through an opening or encounters an obstacle.
When this occurs, the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit.
Note that the principal condition for the occurrence of this phenomena is that the obstacle must be comparable in size (similar size) to the size of the wavelength.
This means the smaller the slit or obstacle (diffracting object), the wider the resulting diffraction pattern, and the greater the obstacle, the narrower de resulting patter.
<h2>2. Diffraction Angle:
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Is the output resulting angle as measured from the surface that is normal (perpendicular) to the slit.
Now, if instead of a slit we have a diffraction grating, different wavelengths of light (different colors is we talk about the visible spectrum) will pass through the grating at different angles.
Speed of the black Mamba = 18 km/h = 5m/s
now the distance that black mamba cover to catch prey
![d = v*t](https://tex.z-dn.net/?f=d%20%3D%20v%2At)
![d = 5 * 2.5 = 12.5 m](https://tex.z-dn.net/?f=d%20%3D%205%20%2A%202.5%20%3D%2012.5%20m)
Now it returns to its hide in 12 s
so average speed of return is given as
![v_{avg} = \frac{12.5}{12} = 1.04 m/s](https://tex.z-dn.net/?f=v_%7Bavg%7D%20%3D%20%5Cfrac%7B12.5%7D%7B12%7D%20%3D%201.04%20m%2Fs)
Part b)
For the whole trip we know that displacement of the mamba is zero
so average velocity of whole trip will be zero
Part c)
For average speed we know that total distance of the black mamba
d = 12.5 + 12.5 = 25 m
total time taken = 2.5 + 12 = 14.5 s
now average speed is given as
![v = \frac{25}{14.5}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7B25%7D%7B14.5%7D)
![v = 1.72 m/s](https://tex.z-dn.net/?f=v%20%3D%201.72%20m%2Fs)