Answer:
the answer should be c
Step-by-step explanation:
Answer:
Please use " ^ " for exponentiation: x^2 + 2x + 8 ≤ 0.
Let's solve this by completing the square:
x^2 + 2x + 8 ≤ 0 => x^2 + 2x + 1^2 - 1^2 + 8 ≤ 0. Continuing this rewrite:
(x + 1)^2 + 7 ≤ 0
Taking the sqrt of both sides: (x + 1)^2 = i*sqrt(7)
Then the solutions are x = -1 + i√7 and x = -1 - i√7
There's something really wrong here. I've graphed your function, x^2 + 2x + 8, and can see from the graph that there are no real roots, but only complex roots. Please double-check to ensure that you've copied down this problem correctly.
2(1/3+6a)
this is the answer
A. p^4/p^7 = p^-3 = 1/p^3
b. 4^3/4^3 = 1
c. 11^2/11^4 = 11^-2 = 1/11^2
d. 6^4/6 = 6^3