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natta225 [31]
3 years ago
12

A water wave passes by a floating leaf that is made to oscillate up and down two complete cycles each second, which means that t

he wave's frequency is
Physics
1 answer:
lina2011 [118]3 years ago
7 0

Answer:

2 Hz.

Explanation:

Frequency is simply defined as the number of appearances of a periodic event occurring per time. It is usually measured in cycles/second.

Now, in this question, we are told that there are 2 cycles for each second.

Thus, we can say that the frequency is 2 cycles/1 s = 2 Hz.

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A particular car engine operates between temperatures of 440°C (inside the cylinders of the engine) and 20°C (the temperature of
Step2247 [10]

One of the concepts to be used to solve this problem is that of thermal efficiency, that is, that coefficient or dimensionless ratio calculated as the ratio of the energy produced and the energy supplied to the machine.

From the temperature the value is given as

\eta = 1-\frac{T_L}{T_H}

Where,

T_L = Cold focus temperature

T_H = Hot spot temperature

Our values are given as,

T_L = 20\° C = (20+273) K = 293 K

T_H = 440\° C = (440+273) K = 713 K

Replacing we have,

\eta = 1-\frac{T_L}{T_H}

\eta = 1-\frac{293}{713}

\eta = 0.589

Therefore the maximum possible efficiency the car can have is 58.9%

4 0
3 years ago
A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter a
avanturin [10]
<span>The answer to your question is choice: D</span>
8 0
3 years ago
Read 2 more answers
The gas tank of a car is filled with a nozzle that discharges gasoline at a constant flow rate. Based on unit considerations of
mojhsa [17]

Answer:

V=\dfrac{dV}{dt}.t

Explanation:

Given that nozzle discharge at constant flow rate.

Volume of tank is V

Lets  constant flow rate =Q

We know that

Q=\dfrac{dV}{dt}\ L^3/s

To find the time t,at a volume V

V = Q .t

V=\dfrac{dV}{dt}.t

Where t is the filling time of volume .

dV/dt is the volume floe rate .

Q is the discharge.

4 0
3 years ago
An ideal gas in an isentropic process has an initial pressure of 200 kPa and relative pressure is 3.482; the final pressure is n
Nostrana [21]

The relative pressure at this state is determined as 0.455.

<h3>Initial pressure of the ideal gas </h3>

The pressure of the ideal gas given rise to the relative pressure is calculated as follows;

R.P = P2/P1

P2 = P1(R.P)

P2 = 200 kPa x (3.482)

P2 = 696.4 kPa

<h3>New relative pressure</h3>

R.P = (P3)/(P2)

R.P = (320)/(696.4)

R.P = 0.455

Thus, the relative pressure at this state is determined as 0.455.

Learn more about relative pressure here: brainly.com/question/15584931

#SPJ1

3 0
2 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 19 cm apart. The sound
Kazeer [188]

Answer:

The wave length of the sound is 66 cm.

The separation between the speakers is 85 cm.

Explanation:

Given that,

Distance between the speakers = 19 cm

Reaching zero at separation  = 52 cm

(a). We need to calculate the wave length of the sound

Using formula of wavelength

\dfrac{\lambda}{2}=\Delta x_{2}-\Delta x_{1}

\lambda=2\times(\Delta x_{2}-\Delta x_{1})

Put the value into the formula

\lambda=2\times(52-19)

\lambda=66\ cm

The wave length of the sound is 66 cm.

(b). if the distance between the speakers continues to increase the intensity will again be a maximum when the separation between the speakers that produces a maximum has increased by one wave length

We need to calculate the separation between the speakers

Using formula of separation

d=19+66

d=85\ cm

The separation between the speakers is 85 cm.

Hence, The wave length of the sound is 66 cm.

The separation between the speakers is 85 cm.

5 0
3 years ago
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