All categories

2 years ago

Does the size of the magnetic field change with the size of the magnet?

Physics

1 answer:

mestny [16]2 years ago

4 0

Answer:

Not all of the time, it can also depend on the strength of the magnet.

Explanation:

say you have a small very strong magnet, that might work just as well as a large but week magnet.

You might be interested in

A 1.00 kg particle has the xy coordinates (-1.20 m, 0.500 m) and a 4.50 kg particle has the xy coordinates (0.600 m, -0.750 m).

just olya [345]

Answer:

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

Explanation:

The center of mass of a system of particles ( $\vec r_{cm}$ ), measured in meters, is defined by this weighted average:

$\vec r_{cm} = \frac{\Sigma_{i=1}^{n}\,m_{i}\cdot \vec r_{i}}{\Sigma_{i=1}^{n}\,m_{i}}$ (1)

Where:

$m_{i}$ - Mass of the i-th particle, measured in kilograms.

$\vec r_{i}$ - Location of the i-th particle with respect to origin, measured in meters.

If we know that $\vec r_{cm} = (-0.500\,m,-0.700\,m)$ , $m_{1} = 1\,kg$ , $\vec r_{1} = (-1.20\,m, 0.500\,m)$ , $m_{2} = 4.50\,kg$ , $\vec r_{2} = (0.600\,m, -0.750\,m)$ and $m_{3} = 4\,kg$ , then the coordinates of the third particle are:

$(-0.500\,m, -0.700\,m) = \frac{(1\,kg)\cdot (-1.20\,m,0.500\,m)+(4.50\,kg)\cdot (0.600\,m,-0.750\,m)+(4\,kg)\cdot \vec r_{3}}{1\,kg+4.50\,kg+4\,kg}$

$(-4.75\,kg\cdot m, -6.65\,kg\cdot m) = (-1.20\,kg\cdot m, 0.500\,kg\cdot m) + (2.7\,kg\cdot m, -3.375\,kg\cdot m) +(4\cdot x_{3},4\cdot y_{3})$

$(4\cdot x_{3}, 4\cdot y_{3}) = (-6.25\,kg\cdot m,-3.775\,kg\cdot m)$

$(x_{3},y_{3}) = (-1.562\,m,-0.944\,m)$

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

5 0

3 years ago

If the speed of sound in air at 20 °C is 342m/s , what will be the increase in speed at 30 °C? with steps

andrew-mc [135]

Answer:

Hmm

Explanation:

I don't know sorry forgive me.

6 0

3 years ago

An object is in circular motion. How will the object behave if the centripetal force is removed

stich3 [128]

The object will sail away in a straight line ... continuing in the same direction it was going when the centripetal force stopped.

3 0

3 years ago

Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th

andriy [413]

Just grab a calculator

3 0

2 years ago

The height of the empire state building is 318 m if a stone is dropped from the top of the building what is the stones velocity

lutik1710 [3]

79 m/s. A stone dropped from the top of the Empire State Building will have a velocity of 79 m/s just before it strikes the ground.

This problem is about free fall, to find the velocity of the stone before it strikes the ground we have to use the equation $v_{f}^{2}=v_{0}^{2}+2gh$ , the initial velocity of the stone is 0 m/s. Then:

$v_{f}^{2}=2gh$

$v_{f}=\sqrt{ 2gh}$

Solving the equation above with g = 9.8 m/s², and h = 318.0 m:

$v_{f}=\sqrt{ 2(9.8m/s^{2})(318.0m)}= 78.95 m/s$

$v_{f}$ ≅ 79 m/s

4 0

2 years ago