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patriot [66]
3 years ago
12

assuming nitrogen behaves like an ideal gas, what volume would 14.0 g of nitrogen gas (N2) occupy at STP? the gas constant is 0.

0821 Lxatm/kxmol
Chemistry
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

V = 22.41 L

Explanation:

Given data:

Mass of nitrogen = 14.0 g

Volume of gas at STP = ?

Gas constant = 0.0821 atm.L/mol.K

Solution:

Number of moles of gas:

Number of moles = mass/molar mass

Number of moles= 14 g/ 14 g/mol

Number of moles = 1 mol

Volume of gas:

PV = nRT

1 atm × V = 1 mol × 0.0821 atm.L/mol.K  × 273 K

V = 22.41 atm.L / 1 atm

V = 22.41 L

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2) Examine the molecules below.<br> Circle the molecules that can also be classified as compounds.
sergejj [24]

Answer:

3rd

Explanation:

its the way they look

4 0
2 years ago
Write the chemical formula for sodium hypobromite.
irga5000 [103]

Answer:

             NaOBr  (or)  Na⁺ ⁻OBr

Explanation:

The Oxo-Acids of Bromine are as follow,

                           Hypobromous Acid  =  HOBr

                           Bromous Acid  =  HOBrO

                           Bromic Acid  =  HBrO₃

                           Perbromic Acid  =  HBrO₄

When these acids are converted to their conjugate bases their names are as follow,

                           Hypobromite  =  ⁻OBr

                           Bromite  =  ⁻OBrO

                           Bromate  =  ⁻OBrO₂

                           Perbromate  =  ⁻OBrO₃

According to rules, the positive part of ionic compound is named first and the negative part is named second. So, Sodium Hypobromite has a chemical formula of Na⁺ ⁻OBr or NaOBr.

6 0
3 years ago
Silicon has 2 isotopes, Silicon-28 with an abundance of 90% and Silicon-30 with an abundance of 10%. Find the AAM for Silicon.
JulsSmile [24]

Answer:

RAM

RAM = (mass \: of \:  ^{28} Si \:  \times \%abundance) + (mass \: of \:  ^{30} Si \:  \times \%abundance) \\ RAM = (28 \times 90\%) + (30 \times 10\%) \\ RAM = 25.2 + 3 \\ RAM = 28.2

5 0
2 years ago
TRIPLE POINTS!!! I NEED HELP!!! PLEASE EXPLAIN TOO!!! What is the energy of a quantum of light with a frequency of 4.31 x 1014 1
Lelechka [254]

Answer:

The answer is

2.86 \times  {10}^{ - 19}  \: J

Explanation:

The energy of a quantum of light can be found by using the formula

<h3>E = hf</h3>

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

f = 4.31 × 10¹⁴ Hz

We have

E = 4.31 × 10¹⁴ × 6.626 × 10-³⁴

We have the final answer as

2.86 \times  {10}^{ - 19}  \: J

Hope this helps you

3 0
3 years ago
What is the percent by mass of oxygen in mg(oh)2
kakasveta [241]

54.868% because well la la la (sorry had to be 20 characters)

3 0
3 years ago
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