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patriot [66]
3 years ago
12

assuming nitrogen behaves like an ideal gas, what volume would 14.0 g of nitrogen gas (N2) occupy at STP? the gas constant is 0.

0821 Lxatm/kxmol
Chemistry
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

V = 22.41 L

Explanation:

Given data:

Mass of nitrogen = 14.0 g

Volume of gas at STP = ?

Gas constant = 0.0821 atm.L/mol.K

Solution:

Number of moles of gas:

Number of moles = mass/molar mass

Number of moles= 14 g/ 14 g/mol

Number of moles = 1 mol

Volume of gas:

PV = nRT

1 atm × V = 1 mol × 0.0821 atm.L/mol.K  × 273 K

V = 22.41 atm.L / 1 atm

V = 22.41 L

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Answer:

1 litre = 1000 millilitres

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Which symbol can be used to indicate the pressure at which a chemical reaction is carried out? 25 degrees Celsius over a right a
jolli1 [7]

Answer:

2 atm

Explanation:

Chemical reactions are carried out at a certain rate. Sometimes that rate is quite slow, so we want to speed things up, which is usually used by increasing temperature, increasing pressure or adding a catalyst (a substance that increases the rate without changing itself).

If this is the case, then, when writing a chemical equation, we state these special conditions over a right arrow.

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- 25°C is a value and unit of temperature

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7 0
3 years ago
Read 2 more answers
The molar mass of a certain gas is 80.6 g. What is the density of the gas in g/L at STP?
vfiekz [6]
Using the ideal gas equation:
PV = nRT

Substituting n with mass / Mr
PV = mRT/Mr

Density = m/V
So rearranging:
Density = PMr/RT

P = 1 atm
R = 0.082 L atm / K mol
T = 273 K
Density = (1 x 80.6) / (0.082 x 273)
Density = 3.6 g / L
3 0
3 years ago
How many moles of lithium are in 83 grams of lithium?
german
1 moles lithium or 6.941 grams
8 0
2 years ago
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PLEASE PLEASE HELP!
valentinak56 [21]

Answer: The number of grams of H_2 in 1620 mL is 1.44 g

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 1620 ml = 1.62 L  (1L=1000ml)

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K

n=\frac{PV}{RT}

n=\frac{1atm\times 16.2L}{0.0821Latm/K mol\times 273K}=0.72moles

Mass of hydrogen =moles\times {\text {Molar mass}}=0.72mol\times 2g/mol=1.44g

The number of grams of H_2 in 1620 mL is 1.44 g

8 0
3 years ago
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