Answer:
Number one is the most acidic, the one in the middle is neutral, and number nine is alkaline.
Answer : The concentration of are 0.127 ppm, 0.127 ppm and 0.254 ppm respectively.
Explanation : Given,
Mass of =
Volume of solution = 2.25 L
First we have to calculate the concentration in terms of g/L.
conversion used :
As we know that,
1 mg/L = 1 ppm
0.127 mg/L = 0.127 ppm
So, the concentration will be 0.127 ppm.
The concentration of in ppm is, 0.127 ppm.
Now we have to calculate the concentration of and .
We assume that, dissociates 100 % in the solution then the balanced reaction will be:
From the reaction we conclude that the mole ratio of is, 1 : 1 : 2. So,
The concentration of = 0.127 ppm
The concentration of = 2 × 0.127 ppm = 0.254 ppm
Answer:
The pKa of Glu is
Explanation:
From the question we are told that
The value of Glu is
The is mathematically represented as
substituting values
Answer:
0.081g
Explanation:
first step:calculate the molar conc of the stock solution
molar conc=mass/molar mass ×1000/vol(ml)
molar mass of Co(N03)2=182.943
molar conc=3g/182.943 ×1000/100ml
=0.163M
To calculate the conc of the resulting solution we apply the dilution principle
n=cv
C1V1=C2V2
C1=conc of stock solution=0.163M
V1=4mL
V2=275ml(final volume)
by making 'C2" the subject C2=0.163×4/275
=0.0024M
by applying the formular for calculating molar conc of a solution,we can calculate the mass of CO(NO3)2 in the reulting solution
molar conc=mass/molar mass ×1000(L)/vol(mL)
mass=0.0024×182.943×275/1000
=0.1193g
Mass of CO(NO3)2 in the resulting solution=0.1199g
since CO+(NO3)2=CO(NO3)2
Percentage by mass of (NO3)2 in CO(NO3)2=(NO3)2/CO(NO3)2
=124/182.943×100
=67.8%
it means 67.8% of 0.1193g is the mass of (NO3)2=0.678×0.1199
=0.081g
Answer: 4.99×10²³ photons
Explanation: The energy of a photon is given as
E= hf
h= Planck constant = 6.626×10^-34Js
f= frequency = c/x
C= speed of light = 3×10^8 m/s
x= wavelength= 525nm= 525×10^-9
E= hc/x
E= 6.626×10^-34 × 3×10^8 m/s /( 525×10^-9)
E= 3.79×10^−19 J/ Photon
E= 3.79×10^−22KJ/Photon
189KJ/3.79×10^−22KJ/photon=
4.99×10²³photons.
Therefore the number of photons is
4.99×10²³photons.