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valina [46]
3 years ago
15

Are these answers correct? I’m a little unsure

Chemistry
1 answer:
Naily [24]3 years ago
8 0

Answer:

yes I think that they are correct

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Due to it's strong attraction to nucleus

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What isapplied in case where the base is not a OH donator
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Pure hydrogen (H₂) is a hazardous substance. Thus, safer and more cost effective techniques have been developed to store it as a
Paha777 [63]

Answer: hello your question has some missing details attached below is the missing details

answer : 25.5%  ( B )

Explanation:

<u>Determine percentage yield </u>

molar mass = 35 g/mol

mass of Li₃N(s) = 70 g

product  LiH(s) = 8.0 g ( actual yield )

theoretical yield ( LiH ) =  4 * 7.95  = 31.8 g

percentage yield = actual yield * 100 / theoretical yield

                            = 8 * 100/31.8

                            = 25.5%

4 0
3 years ago
You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1
jeka57 [31]

Answer:

\boxed{\text{36 mL}}

Explanation:

1. Write the balanced chemical equation.

\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O

2. Calculate the moles of HCOOH

\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}

3. Calculate the moles of NaOH.

\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}

4. Calculate the volume of NaOH

c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}

3 0
3 years ago
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