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valina [46]
3 years ago
15

Are these answers correct? I’m a little unsure

Chemistry
1 answer:
Naily [24]3 years ago
8 0

Answer:

yes I think that they are correct

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During the combustion of a peanut that weighed 0.341 g, the temperature of the 100 mL of water in the calorimeter rose from 23.4
blondinia [14]

Answer:

119 kCal per serving.

Explanation:

The heat energy necessary to elevates water's temperature from 23.4°C to 37.9°C can be calculated by the equation below:

Q = mcΔT

Q: heat energy

m: mass in g

c: specific heat capacity in cal/g°C

ΔT = temperature variation in °C

m is the mass of water, considering the density of water to be 1g/mL, 100 mL of water weights  100g. Therefore:

Q = 100 g x 1.00 cal/g°C x (37.9 - 23.4)°C

Q = 1450 cal

1450 cal ____ 0.341 g peanuts

x             ____  28 g peanuts

x = 119061.58 cal

This means that the cal from fat per serving of peanuts is at least 119 kCal.

3 0
3 years ago
Add them to your friend's list and have them support you along your Brainly journey. Just go to the profile of the person you’d
Makovka662 [10]

Answer:

yup that's how you make friends with people on brainly

8 0
3 years ago
600 s after initiation of a first order reaction 48.5% of the initial reactant concentration remains present. What is the rate c
Ludmilka [50]

Answer:

k=1.20x10^{-3} s^{-1}

Explanation:

For a first order reaction the rate law is:

v=\frac{-d[A]}{[A]}=k[A]

Integranting both sides of the equation we get:

\int\limits^a_b {\frac{d[A]}{[A]}} \, dx =-k\int\limits^t_0 {} \, dt

where "a" stands for [A] (molar concentration of a given reagent) and "b" is {A]0 (initial molar concentration of a given reagent), "t" is the time in seconds.

From that integral we get the integrated rate law:

ln\frac{[A]}{[A]_{0} } =-kt

[A]=[A]_{0}e^{-kt}

ln[A]=ln[A]_{0} -kt

k=\frac{ln[A]_{0}-ln[A]}{t}

therefore k is

k=\frac{ln1-ln0,485}{600}=1,20x10^{-3}

8 0
4 years ago
. Give an example of a salt that is less soluble when the temperature increases
77julia77 [94]

Answer:

cerium (iii) sulfate is less soluble

6 0
3 years ago
Read 2 more answers
An 8 N force is applied to a 2 kg object. What is the magnitude of the object's acceleration? A. 0.25 m/s² B. 4 m/s² C. 6 m/s² D
mel-nik [20]

Answer: 4m/s2 (B)

Explanation:

Force = mass × acceleration

Force given is 8N

Mass=2kg

Acceleration =?

Substitute into the formula

F=ma

8=2a

A=8/2

A=4m/s2

Acceleration used is 4m/s2 (B)

3 0
3 years ago
Read 2 more answers
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