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Neporo4naja [7]
3 years ago
7

Please help me , thank you

Physics
1 answer:
mash [69]3 years ago
5 0

Answer:

Since the reading wasn't specified, it would be most likely A

Explanation:

A is the most similar to a protoplanetary disk, so it'd be A most likely

You might be interested in
what is the magnitude of the gravitational force acting on the earth due to the sun? express your answer in newtons.
Alborosie

The gravitational force the sun experiences from the earth is 3.48×10²²N, which is exactly the same as the force the sun experiences from the earth.

  • Gravity is a force that develops as a result of the attraction between mass-containing objects. The mass of the object has a direct relationship to the strength of this attraction. r equals the separation of two objects.

F = G (M₁M₂)/r²

Where, F  the gravitational force

G=6.67×10⁻¹¹Nm²kg⁻² gravitational constant

M₁=5.98×10²⁴kg  mass of earth

M₂= 1.99×10³⁰ kg the mass of the sun

r =15×10¹⁰ m is the distance between sun and earth

Putting all the values in above equation,

F = 6.67×10⁻¹¹Nm²kg⁻²(5.98×10²⁴kg 1.99×10³⁰ kg)/15×10¹⁰ m

On solving the above equation we get,

F = 3.48×10²²N

To know more about gravitational force

brainly.com/question/12830265

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5 0
1 year ago
What is the force on an object that goes from 35 m/s to 85 m/s in 20 seconds and has a mass of 148 kg
Sever21 [200]
F=ma
F = 148×(85-35)÷20
F = 148×(50÷20)
F = 148×2.5
F = 370N
3 0
3 years ago
From a vantage point very close to the track at a stock car race, you hear the sound emitted by a moving car. You detect a frequ
V125BC [204]

Answer:

55.8 m/s

Explanation:

f = Actual frequency of sound emitted by car

f' = frequency observed when the car moves = (0.86)f

V = Speed of sound = 343 m/s

v = Speed of car

Frequency observed is given as

f' = \frac{Vf}{V+v}

(0.86) = \frac{(343)}{343 + v}\\(0.86) = \frac{(343)}{343 + v}\\294.98 + (0.86) v = 343 \\v = 55.8 ms^{-1}

6 0
3 years ago
The rate at which the earth's surface loses heat and keeps earth temperature at which living things can survive
agasfer [191]
<span>I believe it's insulation.</span>
5 0
3 years ago
A 86g ball is dropped vertically to the floor from a height of 2.87m and bounces to a height of 1.28. What is the magnitude of t
irga5000 [103]

Answer:

The impulse received by the ball from the floor during the bounce is approximately 1.11329438 m·kg/s

Explanation:

The given mass of the ball, m = 86 g = 0.089 kg

The height from which the ball is dropped, H = 2.87 m

The height to which the ball bounces, h = 1.28 m

Mathematically, we have;

Δp = F·Δt

Where;

Δp = The change in momentum = m·Δv

F = The applied force

Δt = The time of contact with the force

The velocity of the ball just before it touches the ground, v₁ = -√(2·g·H)

The velocity with which the ball leaves, v₂ = √(2·g·h)

The change in momentum, Δp = m·(v₂ - v₁)

∴ Δp = m·(√(2·g·h) - (-√(2·g·H))) = m·(√(2·g·h) +√(2·g·H) )

The impulse, Δp, received by the ball from the floor during the bounce is given as follows;

Δp = 0.089 kg × (√(2 × 9.8 m/s² × 1.28 m) + √(2 × 9.8 m/s² × 2.87 m)) ≈ 1.11329438 m·kg/s

The impulse received by the ball from the floor during the bounce, Δp ≈ 1.11329438 m·kg/s

6 0
3 years ago
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