Answer:
Heat of vaporization will be 22.59 j
Explanation:
We have given mass m = 10 gram
And heat of vaporization L = 2.259 J/gram
We have to find the heat required to vaporize 10 gram mass
We know that heat of vaporization is given by
, here m is mass and L is latent heat of vaporization.
So heat of vaporization Q will be = 10×2.259 = 22.59 J
D. The atomic mass in amu is basically the number or nuclei since the mass of the electrons is negligible. For a given atom (element) the number of protons is fixed. Say the element has 10 protons. If the atomic weight is 14 atomic mass units (amu), you know that there are 4 neutrons, since both neutrons and protons are 1 amu each and there are 10 protons
Answer:bowling ball has greater kinetic energy
Explanation:
Kinetic energy of bowling ball:
mass=m=5kg
Velocity=v=6m/s
Kinetic energy =ke
Ke=0.5 x m x v x v
Ke=0.5 x 5 x 6 x 6
Ke=90J
Kinetic energy of ship:
mass=m=120000kg
velocity=v=0.02m/s
Ke=0.5 x m x v x v
Ke=0.5 x 120000 x 0.02 x 0.02
Ke=24J
Answer:
An equipotential surface is circular in the two-dimensional. Since the electric field lines are directed radially away from the charge, hence they are opposite to the equipotential lines. Therefore, the electric field is perpendicular to the equipotential surface.
They are poor conductors because they keep the heat trapped in one spot, while other materials like metal let the heat go through itself.