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3 years ago

true or false a basketball sitting on a horizontal surface will NOT feel any friction even if the surface might be rough

Physics

1 answer:

Sidana [21]3 years ago

7 0

Answer:

False

Explanation:

A basketball sitting on a horizontal surface will experience static friction which prevents it from moving. Static friction is higher than when the ball and surface are in motion relative to each other. Objects that are resting on horizontal surface experience static friction which gives way to kinetic friction where the two objects, the surface and the object at rest, move relative to each other. The statement in the question is incorrect.

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A solid sphere, solid cylinder, and a hollow pipe all have equal masses and radii and are of uniform density. If the three are r

scZoUnD [109]

Answer:

A ) SOLID SPHERE

Explanation:

Moment of inertia of solid sphere = 2/5 M R²

= M K² , K is called radius of gyration

K = √2/5 R

Moment of inertia of solid cylinder = 1/2 M R²

= M K² , K is called radius of gyration

K = 1 /√2 R

Moment of inertia of solid sphere = M R²

= M K² , K is called radius of gyration

K = R

For rolling on inclined plane , acceleration

a = $\frac{gsin\theta}{1+\frac{K^2}{R^2} }$

Putting the value of K for solid sphere

a for solid sphere

a = g sinθ / ( 1 +2/5)

a = .714 g sinθ

Putting the value of K for solid cylinder

a for solid cylinder

a = g sinθ / ( 1 +1/2)

a = .666 g sinθ

Putting the value of K for hollow pipe

a for hollow pipe

a = g sinθ / ( 1 +1 )

a = . 5 g sinθ

So we see that acceleration a for solid sphere is greatest and a for hollow pipe is the least. Hence solid sphere will reach the bottom earliest and hollow pipe will reach the bottom the latest.

7 0

3 years ago

Will name brainliest please pleas answer

Greeley [361]

3 is the answer teeeeeeeeeheeeeeeeee

6 0

3 years ago

Which sources of associated with the line emission spectrum?

Lerok [7]

Answer:

Answer if this question neon street sign

Explanation:

may this answer is helpful for you

3 0

3 years ago

1) At which lettered point or points is the object moving the fastest?

emmainna [20.7K]

Here we have a time-position graph with some points marked on it, and we want to analyze some points in it.

1) The object is moving the fastest in the point where the slope of the curve is the largest.

In this case, the point is D.

2) Remember that the graph evolves to the right, so, if at any point, the right side is above the left side, then at that particular point the object is moving to the left (negative x-axis)

In this case, the points are:

C, D, and E.

3) The object speeds up when the curvature of the curve changes and the slope increases, for example, from B onwards, the speed increases.

Then at point C the speed is increasing.

4) Opposite to what we said before, if the slope decreases then the object is slowing down.

In this case we can see that the slope decreases after A and after E.

5) When the object is turning around?

This is easy, we can see that the object goes to the right (positive x-axis) until it reaches B and then goes back, then at point B the object turns around.

If you want to learn more, you can read:

brainly.com/question/11290689

8 0

3 years ago

A box is moved 20 m across a smooth floor by a force making a downward angle with the floor, so that there is effectively a 10 N

Usimov [2.4K]

Answer:

100 J

Explanation:

From the question, The work done by the forces in moving the box is given as

W = FxdcosФ+Fydcosα................... Equation 1

Where W = Work done, Fx = force acting parallel to the floor, d = distance moved by the box, Ф = angle the parallel force makes with the floor, Fy = force acting perpendicular to the floor, α = angle the perpendicular force make with the floor.

Give: Fx = 10 N, d = 20 m, Fy = 5 N, Ф = 0°, α = 90°

Substitute into equation 1

W = 10×10×cos0°+5×20×cos90°

W = 10×10×1+0

W = 100 J.

Note: The work done by the perpendicular force is zero

Hence the work done = 100 J

5 0

3 years ago