Question

A 0.450 L sample of nitrogen gas is collected under a pressure of 2.30 atm and a temperature of 60.0 degrees Celsius. The sample is transferred to a 0.600 L container and the pressure drops to 1.54 atm. What is the new temperature of this gas (in K)?

Answer 1

Answer:

326.56K

Step-by-step explanation:

Step one:

Given

V1=0.45L

P1=2.3atm

T1=60 °

V2=0.6L

P2=1.54atm

T2=?

Step two:

Required:

T2

Applying the partial gas formula

$\frac{P1V1}{T1}=\frac{P2V2}{T2}$

$\frac{2.3*0.45}{60}=\frac{1.54*0.6}{T2}$

cross multiply we have

T2=(1.54*0.6*60)/2.3*0.45

T2=55.44/1.035

T2=53.56 °

in kelvin, we need to add 273

=273+53.56=326.56K

T2=326.56K

The new temperature of this gas (in K) is 326.56K