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gayaneshka [121]
3 years ago
5

An atom that ______ electrons is called a positive ion. A. has 0 B. has 8 C. loses D. gains

Chemistry
2 answers:
Kitty [74]3 years ago
8 0

Answer:

Gains

Explanation:

It gets more electrons

Lena [83]3 years ago
7 0
Loses because then it will have a positive charge
You might be interested in
­­2K + 2HBr → 2 KBr + H2
Inessa [10]

Answer:

\large \boxed{\text{0.0503 g}}

Explanation:

The limiting reactant is the reactant that gives the smaller amount of product.

Assemble all the data in one place, with molar masses above the formulas and masses below them.

M_r:   39.10    80.41                2.016  

            2K  +  2HBr ⟶ 2KBr + H₂

m/g:     5.5      4.04

a) Limiting reactant

(i) Calculate the moles of each reactant  

\text{Moles of K} = \text{5.5 g} \times \dfrac{\text{1 mol}}{\text{31.10 g}} = \text{0.141 mol K}\\\\\text{Moles of HBr} = \text{4.04 g} \times \dfrac{\text{1 mol}}{\text{80.91 g}} = \text{0.049 93 mol HBr}

(ii) Calculate the moles of H₂ we can obtain from each reactant.

From K:  

The molar ratio of H₂:K is 1:2.

\text{Moles of H}_{2} = \text{0.141 mol K} \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol K}} = \text{0.0703 mol H}_{2}

From HBr:  

The molar ratio of H₂:HBr is 3:2.  

\text{Moles of H}_{2} = \text{0.049.93 mol HBr } \times \dfrac{\text{1 mol H}_{2}}{\text{1 mol HBr}} = \text{0.024 97 mol H}_{2}

(iii) Identify the limiting reactant

HBr is the limiting reactant because it gives the smaller amount of NH₃.

b) Excess reactant

The excess reactant is K.

c) Mass of H₂

\text{Mass of H}_{2} = \text{0.024 97 mol H}_{2} \times \dfrac{\text{2.016 g H}_{2}}{\text{1 mol H}_{2}} = \textbf{0.0503 g H}_{2}\\ \text{The mass of hydrogen is $\large \boxed{\textbf{0.0503 g}}$ }

3 0
3 years ago
Consider the following reaction:
PIT_PIT [208]

Answer:

Kc = 3.1x10²

Explanation:

At equilibrium, the velocity of product formation is equal to the velocity of reactants formation. For a generic reaction, the equilibrium constant (Kc) is:

aA + bB ⇄ cC + dD

Kc = \frac{[C]^c*[D]^d}{[A]^a*[B]^b}

Where [X] is the molar concentration of X, and the solid substances are not considered (because it's activity is 1, for the other substances, the activity is substituted for the molar concentration, which forms the equation above).

For the reaction given, let's make an equilibrium chart:

Fe³⁺(aq) + SCN⁻(aq) ⇄ FeSCN²⁺(aq)

1.1*10⁻³       8.2*10⁻⁴           0                  <em> Initial</em>

  -x               -x                  +x                  <em>Reacts</em> (stoichiometry is 1:1:1)

1.1*10⁻³ -x   8.2*10⁻⁴ -x       x                 <em>  Equilibrium</em>

x = 1.8*10⁻⁴ M, so the molar concentrations at equilibrium are:

[Fe⁺³] = 1.1*10⁻³ - 1.8*10⁻⁴ = 9.2*10⁻⁴ M

[SCN⁻] = 8.2*10⁻⁴ - 1.8*10⁻⁴ = 6.4*10⁻⁴ M

[FeSCN⁺²] = 1.8*10⁻⁴ M

Kc = [FeSCN⁺²]/([Fe⁺³]*[SCN⁻])

Kc = (1.8*10⁻⁴)/(9.2*10⁻⁴*6.4*10⁻⁴)

Kc = 306 = 3.1x10²

6 0
3 years ago
What is the concentration of H+ ions at a pH = 11?
natta225 [31]

Answer:

\huge 1 × {10}^{-11} \: \: M

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

Since we are finding the H+ ions we find the antilog of the pH

So we have

11 =  -  log({H}^{+})  \\ {H}^{+} =  {10}^{ - 11}

We have the final answer as

1 × {10}^{-11} \: \: M

Hope this helps you

6 0
3 years ago
Write a balanced chemical equation based on the following description:
kupik [55]

The balanced chemical equation for the reaction is

<h3>6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) +  N₂(g) </h3>

From the question given above, we were told that:

solid cesium reacts with solid cesium nitrite to form solid cesium oxide and nitrogen gas.

The equation for the reaction can be written as follow:

Caesium => Cs

Caesium nitrite => CsNO₂

cesium oxide => Cs₂O

nitrogen gas => N₂

Caesium + Caesium nitrite —> Caesium oxide + Nitrogen gas

<h3>Cs + CsNO₂ —> Cs₂O +  N₂</h3>

The above equation can be balance as follow:

Cs + CsNO₂ —> Cs₂O +  N₂

There are 2 atoms of N on the right side and 1 atom on the left side. It can be balance by writing 2 before CsNO₂ as shown below:

Cs + 2CsNO₂ —> Cs₂O +  N₂

There are 2 atoms of Cs on the right side and a total 3 atoms on the left side. It can be balance by writing 6 before Cs and 4 before Cs₂O as shown below:

6Cs(s) + 2CsNO₂(s) —> 4Cs₂O(s) +  N₂(g)

Now the equation is balanced

Learn more: brainly.com/question/11502387

5 0
3 years ago
Read 2 more answers
BeH2 has no lone pairs of electrons. What's the structure of this molecule?
PolarNik [594]
The shape of BeH2 is linear.
8 0
3 years ago
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