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3 years ago

Please help! Please!!!

Chemistry

1 answer:

lys-0071 [83]3 years ago

7 0

Answer:

A and D

Explanation:

unsaturated hydrocarbons have double or triple bonds

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A car with a mass of 1,200 kilograms is moving around a circular curve at a uniform velocity of 20 meters per second. The centri

Helga [31]

The answer is 80 m.

Centripetal force (F) is a force that makes body move around a circular curve. The unit of force is N (N = kg * m/s²).
It can be represented as:
$F= \frac{m* v^{2} }{r}$
where:
m - mass
v - velocity
r - radius of the curve

We have:
m = 1,200 kg
V = 20 m/s
F = 6,000 N = 6,000 kg * m/s²

We need radius of the curve:
r = ?

So, if <span> $F= \frac{m* v^{2} }{r}$ , then:
</span> $r= \frac{3* v^{2} }{F}$
⇒ $r = \frac{1200 kg * (20m/s)^{2} }{6000 kg*m/s^{2} }$
⇒ $r= \frac{1200*400*kg*m^{2}*s^{2} }{6000kg*m/s^{2} }$
⇒ $r= \frac{480,000m}{6000}$
⇒ $r=80m$

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4 years ago

Which of the following elements would be likely to form an anion?

Vsevolod [243]

B because chlorine is a halogen. This means that it already 7 valence electrons and only needs 1 more to have a complete outer shell.

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3 years ago

An empty beaker weighs 20g and when filled with

Sphinxa [80]

Answer: The density of kerosene is $2.7g/cm^3$

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given : Mass of kerosene = mass of beaker with kerosene - mass of empty beaker = 60 g - 20 g = 40 g

Volume of kersone = $15cm^3$

Putting in the values we get:

$Density=\frac{40g}{15cm^3}$

$Density=2.7g/cm^3$

Thus the density of kerosene is $2.7g/cm^3$

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3 years ago

I JUST GOT RICKROLLED WHAT DO I DO PLEEEAASSEEEE HELP

soldi70 [24.7K]

Answer:

contemplate your life...what you are doing here...what it means to live in our society...THEN...pass it on :0

Explanation:

mind blown ~\_(* - *)_/~

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4 years ago

Read 2 more answers

Now if your lab partner determined that there were 1.552 x 1022 atoms of H in an unknown sample of C2H4Cl2, how many milligrams

STALIN [3.7K]

To determine the mass of the sample in milligrams in this problem, we use the avogadro's number to convert from atoms to moles, relate the moles of element in the sample to the mole present and the molar mass of the sample. We do as follows:

1.552 x 10^22 atoms H ( 1 mol H / 6.022x10^23 atoms H ) ( 1 mol C2H4Cl2 / 4 mol H ) ( 98.96 g C2H4Cl2 / 1 mol C2H4Cl2 ) = 0.625 g C2H4Cl2 = 625 mg <span>C2H4Cl2</span>

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4 years ago