In POCl₃, Phosphorous will form 5 bonds. The bonds formed are as,
* Two Bonds (Double Bond) with Oxygen atom
* Three Bonds (Single Bond each) with three Chlorine atoms.
Formal charge: Formal Charge is calculated using following formula,
Formal Charge = [# of Valence e⁻s] - [e⁻s in lone pairs + 1/2 e⁻s in bonding e⁻s]
Valence electrons of P = 5
e⁻s in lone pair = 0
e⁻s in Bonding = 10
So,
Formal Charge = [5]-[0+10/2]
Formal Charge = [5]-[5]
Formal Charge = 0
Answer:
(i) Oxidizing Agent: NO2 / Reducing Agent NH3-
(ii) Oxidizing Agent AgNO3 / Reducing Agent Zn
Explanation:
(i) 8NH3( g) + 6NO2( g) => 7N2( g) + 12H2O( l)
In this reaction, both two reactants contain nitrogen with a different oxidation number and produce only one product which contains nitrogen with a unique oxidation state. So, nitrogen is oxidized and reduced in the same reaction.
Nitrogen Undergoes a change in oxidation state from 4+ in NO2 to 0 in N2. It is reduced because it gains electrons (decrease its oxidation state). NO2 is the oxidizing agent (electron acceptor).
Nitrogen Changes from an oxidation state of 3- in NH3 to 0 in N2. It is oxidized because it loses electrons (increase its oxidation state). NH3 is the reducing agent (electron donor)
(ii) Zn(s) +AgNO3(aq) => Zn(NO3)2(aq) + Ag(s)
Ag changes oxidation state from 1+ to 0 in Ag(s).
Ag is reduced because it gains electrons and for this reason and AgNO3 is the oxidizing agent (electron acceptor)
Zn Changes from an oxidation state of 0 in Zn(s) to 2+ in Zn(NO3)2. It is oxidized and for this reason Zn is the reducing agent (electron donor).
Balanced equation:
Zn(s) +2AgNO3(aq) => Zn(NO3)2(aq) + 2Ag(s)
Answer:percent composition
Explanation:
Answer:
The work done by the gas is 117,300 Joules.
Explanation:
Pressure applied on the gas , P= 102.0 kPa = 102000 Pa ( 1kPa = 1000 Pa
Change in volume of the gas ,ΔV= 
Here the work is done by system so, the value of work done will be negative.
The work done by the gas is 117,300 Joules.
