Can anyone please help!!!
1 answer:
Answer:
Question 9
(a) The distance, Jalaj walks in one day is 4.4 km
(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8
Question 10
(b) The difference between the largest and smallest areas is 2,400 m²
Step-by-step explanation:
Question 9
(a) The distance Jalaj walks in 5 days = 22 km
Whereby Jalaj walks equal distance every day, we have;
The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day
The distance, Jalaj walks in one day = 4.4 km
(b) The amount he raises for every kilometer he walks = $1.60
The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60 = $8
Question 10
(b) The given side length of the square = 120 meters to the nearest 10 meters
Therefore;
The maximum dimension for the side length of the square = 120 + 10/2 = 125
The largest possible area of the square, = 125 m × 125 m = 15,625 m²
The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m
The smallest possible area of the square, = 115 m × 115 m = 13,225 m².
The difference between the largest and smallest areas, -
= 15,625 - 13,225 = 2,400 m².
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Answer:
The equation of the line is y - 3 = 2.5(x - 2) ⇒ D
Step-by-step explanation:
The rule of the slope of a line is m = , where
- (x1, y1) and (x2, y2) are two points on the line
The point-slope form of a line is y - y1 = m(x - x1), where
- (x1, y1) is a point on the line
From the given figure
∵ The line passes through points (2, 3) and (0, -2)
∴ x1 = 2 and y1 = 3
∴ x2 = 0 and y2 = -2
→ Substitute them in the rule of the slope to find it
∵ m =
∴ m = 2.5
→ Substitute the values of m, x1, y1 in the form of the equation above
∵ m = 2.5, x1 = 2, y1 = 3
∵ y - 3 = 2.5(x - 2)
∴ The equation of the line is y - 3 = 2.5(x - 2)