Missing data in the text of the exercise: The molar concentration of Zinc is 10 times the molar concentration of copper.
Solution:
1) First of all, let's calculate the standard electrode potential difference at standard temperature. This is given by:

where

is the standard potential at the cathode, while

is the standard potential at the anode. For a Daniel Cell, at the cathode we have copper:

, while at the anode we have zinc:

. Therefore, at standard temperature the electrode potential difference of the Daniel Cell is

2) To calculate

at any temperature T, we should use Nerst equation:
![E^0(T)=E^0- \frac{R T}{z F} \ln \frac{[Zn]}{[Cu]}](https://tex.z-dn.net/?f=E%5E0%28T%29%3DE%5E0-%20%5Cfrac%7BR%20T%7D%7Bz%20F%7D%20%5Cln%20%20%5Cfrac%7B%5BZn%5D%7D%7B%5BCu%5D%7D%20%20)
where


is the temperature in our problem

is the number of electrons transferred in the cell's reaction

is the Faraday's constant
![[Zn]](https://tex.z-dn.net/?f=%5BZn%5D)
and
![[Cu]](https://tex.z-dn.net/?f=%5BCu%5D)
are the molar concentrations of zinc and in copper, and in our problem we have
![[Zn]=10[Cu]](https://tex.z-dn.net/?f=%5BZn%5D%3D10%5BCu%5D)
.
Using all these data inside the equation, and using

, in the end we find: