Question

. The area of a rectangular trampoline is 112 ft2. The length of the trampoline is 6 ft greater than the width of the trampoline. This situation can be represented by the equation w 2 + 6 w - 112 = 0. What is the width of the trampoline in feet?

Answer 1

Answer:

The width of the trampoline is 8 feet.

Step-by-step explanation:

Area of rectangular trampoline = 112 $ft^{2}$

let the width of the trampoline be represented by w, but,

length = w + 6

Given that the situation has been represented by the equation;

$w^{2}$ + 6w - 112 = 0

$w^{2}$ + 14w - 8w - 112 = 0

($w^{2}$ + 14w) - (8w + 112)

w(w + 14) - 8(w + 14)

(w + 14)(w - 8)

So that;

w + 14 = 0 or w - 8 = 0

w = -14 or w = 8

Thus, w = 8

The width of the trampoline is 8 feet.