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AfilCa [17]
2 years ago
13

How many grams of oxygen are produced when 3.0 moles of potassium chlorate decompose completely?

Chemistry
1 answer:
Elena-2011 [213]2 years ago
4 0
ሠረዕጎነዘሠጋዕጕነጋሠሀነዘነጋዕዘቿዘነዘ :)
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When an equation is used to calculate the amount of product that will form during a reaction, then the value obtained is called
bekas [8.4K]
This would be the theoretical yield. This is the amount of product that should be obtained in the end of a reaction, given that none of the reactants are wasted in the creation of the product. This is unlikely to be exactly obtained, however, due to waste products being formed in the process.
6 0
3 years ago
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PLEASE HELP ASAP I'M SO STRESSED
bazaltina [42]

Answer:

160.3g

Explanation:

We know the equation:

No of moles = mass ÷ Mass of element

We need to find the mass, so make mass the subject of the formula.

Mass = No. of moles × mass of element

Mass = 5 × 32.06

Mass = 160.3g

4 0
2 years ago
Plsplsplsplsplsplsplsplsplspls help
MA_775_DIABLO [31]

Answer:

this is difficult but simple to answer

Explanation:

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6 0
2 years ago
For each equation , write all possible mole ratios . A. 2HgO(s)>2Hg(l)+O2(g) B. 4NH3(g)+6NO(g)>5N2(g)+6H2O(l)
Dafna11 [192]

A) For balanced chemical equation: 2HgO(s) → 2Hg(l) + O₂(g).

1) Mole ratio 1: n(HgO) : n(Hg) = 2 : 2 (1 : 1).

2) Mole ratio 2: n(HgO) : n(O₂) = 2 : 1.

3) Mole ratio 3: n(Hg) : n(O₂) = 2 : 1.

B) Balanced chemical equation: 4NH₃(g) + 6NO(g) → 5N₂(g) + 6H₂O(l).

1) Mole ratio 1: n(NH₃) : n(NO) = 4 : 6 (2 : 3).

2) Mole ratio 2: n(NH₃) : n(N₂) = 4 : 5.

3) Mole ratio 3: n(NH₃) : n(H₂O) = 4 : 6 (2 : 3).

4) Mole ratio 4: n(NO) : n(N₂) = 6 : 5.

5) Mole ratio 5: n(NO) : n(H₂O) = 6 : 6 (1 :1).

6) Mole ratio 6: n(N₂) : n(H₂O) = 5 : 6.

3 0
3 years ago
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PLZ HELP?! 50 points <br><br> Write the correct IUPAC name for the following compound
slamgirl [31]

Answer:

2-ethly-3-5 dimethylheptam

Explanation:

trust meeeeee

3 0
2 years ago
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