Answer:
0.5 moles of LiOH will absorb 5.6 L of 
Explanation:
According to law of conservation of mass, the sum of mass on the reactant side must be equal to the sum of mass on product side.
The balanced chemical equation is:
2 moles of LiOH absorb 1 mole of i.e. 22.4 Liters at STP
0.5 moles of LiOH absorb
=
0.5 moles of LiOH will absorb 5.6 L of
Answer:
The mean free path = 2.16*10^-6 m
Explanation:
<u>Given:</u>
Pressure of gas P = 100 kPa
Temperature T = 300 K
collision cross section, σ = 2.0*10^-20 m2
Boltzmann constant, k = 1.38*10^-23 J/K
<u>To determine:</u>
The mean free path, λ
<u>Calculation:</u>
The mean free path is related to the collision cross section by the following equation:
where n = number density
Substituting for P, k and T in equation (2) gives:
Next, substituting for n and σ in equation (1) gives:
The answer is A) Aluminum Bromide
hope this helps :)
In order to calculate for the amount of CaCl2 and water used we need to multiply the total amount mixture to the percentage of each component. Since we are given a two component mixture CaCl2-water with 40% CaCl2 by mass, therefore we have 60% water.
Amount of CaCl2 = 0.40*(370.9) =148.36 g of CaCl2
Amount of Water = 0.60*(370.9) = 222.54 g of Water
The density of the unknown metal, given the data is 1.67 g/mL
<h3>What is density? </h3>
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
With the above formula, we can determine the density of the unknown metal. Details below:
<h3>How to determine the density </h3>
- Mass of unknown metal = 20 - 0 = 20 g
- Volume of unknown metal = 12 - 0 = 12 mL
- Density of unknown metal =?
Density = mass / volume
Density of unknown metal = 20 / 12
Density of unknown metal = 1.67 g/mL
Thus, the density of unknown metal is 1.67 g/mL
Learn more about density:
brainly.com/question/952755
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