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zimovet [89]
3 years ago
12

What is the gravitational potential energy of a 3.0-kg rock that is 12.4 m above the ground?

Physics
1 answer:
makkiz [27]3 years ago
7 0

Answer:

Explanation:

PE = mgh where m is mass, g is the pull of gravity, and h is the height to which the object can possibly fall.

PE = 3.0(-9.8)(-12.4) so

PE = 360 J, rounded to the correct number of sig figs.

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Explanation:

The electric field at a distance r from the charged particle is given by :

E=\dfrac{kq}{r^2}

k is electrostatic constant

if r = 2 m, electric field is given by :

E_1=\dfrac{kq}{(2)^2}\\\\=\dfrac{kq}{4}\ .....(1)

If r = 1 m, electric field is given by :

E_2=\dfrac{kq}{r_2^2}\\\\=\dfrac{kq}{1}\ ....(2)

Dividing equation (1) and (2) we get :

\dfrac{E_1}{E_2}=\dfrac{\dfrac{kq}{4}}{kq}\\\\\dfrac{E_1}{E_2}=\dfrac{1}{4}\\\\E_2=4\times E_1

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