The temperature : 263.016 K
<h3>Further explanation</h3>Combined with Boyle's law and Gay Lussac's law
P1 = initial gas pressure (N/m² or Pa)
V1 = initial gas volume (m³)
P2 = gas end pressure
V2 = the final volume of gas
T1 = initial gas temperature (K)
T2 = gas end temperature
P1=760 mmHg
V1= 4 L
T1 = 275 K
P2=704 mmHg
V1=4.13 L
Answer: The molar solubility of barium fluoride is 0.0183 moles/liter.
Explanation:
The equation for the reaction will be as follows:
By Stoichiometry,
1 mole of gives 2 moles of
and 1 mole of
Thus if solubility of is s moles/liter, solubility of
is s moles/liter and solubility of
is 2s moles/liter
Therefore,
Thus the molar solubility of barium fluoride is 0.0183 moles/liter.