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timofeeve [1]
3 years ago
12

Why is it possible for star that is no longer in space to still appear to shine?

Chemistry
2 answers:
Kamila [148]3 years ago
5 0
There is a difference in the time we see things from space. There is a delay so we see things after they happen
Helen [10]3 years ago
5 0

Answer:

Explanation:

stars are so far away from Earth that, even through large telescopes, they appear only as pinpoints. And it’s easy for Earth’s atmosphere to disturb the pinpoint light of a star. As a star’s light pierces our atmosphere, each single stream of starlight is refracted – caused to change direction, slightly – by the various temperature and density layers in Earth’s atmosphere. You might think of it as the light traveling a zig-zag path to our eyes, instead of the straight path the light would travel if Earth didn’t have an atmosphere.

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Fill in the coefficients that will balance the following reaction: a0NaCl + a1FeO → a2Na2O + a3FeCl2
Helen [10]

Answer:

2NaCl + FeO —-> 2Na2O + FeCl2

Explanation:

4 0
4 years ago
Is material that has a density of 0.2g/ml good for building a bridge or for making couch cushions
lisov135 [29]
D = 0.2 g / ml = 0.2 g / cm³
For example, density of steel is 7.85 g / cm³.
Density of pure water is 1.0 g/cm³. An object which has a density < 1.0 g/cm³ will float in water.
Answer: Material that has a density of 0.2 g/ml ( 0.2 g/cm³ ) is good for making couch cushions. 
8 0
3 years ago
Read 2 more answers
i got a 9/10 on my science quiz today:D it was open notebook so it was easy. THEN i took another quiz and got 10/10!!! :DD
maw [93]
Good job!!!!
Explanation: congratulations
7 0
3 years ago
Read 2 more answers
Look at the following equation.
Ronch [10]

Answer:

A

Explanation:

_N2 + _H2 - _NH3

LHS RHS

N=2×1=2 N=1×2=2

H=2×3=6 H=3×2=6

1,3,2

4 0
3 years ago
Now you will solve the same problem as above, but using the quadratic formula instead of iterations, to show that the same value
Dafna1 [17]

Answer:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

[H₃O⁺] = 0.000859M

Explanation:

As HNO₂ is a weak acid, its equilibrium in water is:

HNO₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + NO₂⁻(aq)

Equilibrium constant, ka, is defined as:

ka = 4.5x10⁻⁴ = [H₃O⁺] [NO₂⁻] / [HNO₂] <em>(1)</em>

Equilibrium concentration of each specie are:

[HNO₂] = 0.00250M - x

[H₃O⁺] = x

[NO₂⁻] = x

Replacing in (1):

4.5x10⁻⁴ = x × x / 0.00250M - x

1.125x10⁻⁶ - 4.5x10⁻⁴x = x²

0 = x² + 4.5x10⁻⁴x - 1.125x10⁻⁶

As the quadratic equation is ax² + bx + c = 0

Coefficients are:

a: 1

b: 4.5x10⁻⁴

c: 1.125x10⁻⁶

Now, solving quadratic equation:

x = -0.0013 → False answer, there is no negative concentrations.

<em>x = 0.000859</em>

As [H₃O⁺] = x; <em>[H₃O⁺] = 0.000859M</em>

I hope it helps!

6 0
3 years ago
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