Answer:
A mass is suspended on a spring. The spring is compressed so that the mass is located 5 cm above its rest position. The mass is released at time t = 0 and allowed to oscillate. It is observed that the mass reaches its lowest points after it is released. Find an equation that describes the motion of the mass.
1/2
Explanation:
We do not start at y=0y=0 so it is better to use a cosine curve. The hanging string is compressed to a position that is y=5y=5 units above the rest position. Hence, |a|=5∣a∣=5. Also, since we begin at positive values, then a=5a=5.
We begin at the highest point y=5y=5.
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A copper wire of diameter 3.256mm carries a current of 6.25mA. the potential difference is mathematically given as
V=2.0657*10^{-4}
<h3>What is the potential difference across a 200m length of the wire?</h3>
Generally, the equation for is mathematically given as
R=Pl/A
Therefore
R=1.72*10^{-8}*2.00/\pi*(1.628)^2*10^{-6}
R=1.652*10^{-2}
In conclusion,
V=IR
V=12.5*10^{-3}*1.652*10^{-2}
V=2.0657*10^{-4}
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Answer:
liquid
Explanation:
due to high temperatures in the magma chamber all solids liquidify on reaching the surface with colder temperatures it now solidify to form igneous rock
Answer:
The work done in winding the spring gets stored in the wound up spring in the form of elastic potential energy (i.e potential energy due to change in shape). ... During this process, the potential energy stored in it gets converted to kinetic energy. This turns the wheels of the toy car.
Explanation: