What happens when calcium reacts with chlorine?

Physics

1 answer:

larisa86 [58]3 years ago

5 0

Answer:

Calcium chloride in an ionic compound. The calcium atom loses two electrons, and each chlorine atom gains one electron, to form a full outer shell of electrons.

You might be interested in

BRAINLIEST!!! how does the electric force between two charged particles change if the distance between them is reduced by a fact

Bogdan [553]

Answer:

F = K Q1 * Q2 / R^2 force between 2 charged particles

F2 / F1 = R1^2 / R2^2 = (R1 / R2)^2 = (R1 / R1 /2)^2 = 2^2 = 4

d) the force would be increased by a factor of 4

3 0

2 years ago

A 0.8 kg object displaces 500 mL of water. What is its specific gravity?

Airida [17]

The specific gravity is how the density of the object compares to the density of water. Water's density is 1gram per milliliter. We just need to figure out the density of the object.

The object is .8 kg and it displaces 500mL of water, so the density is the mass divided by the volume. Since the density of water is given in grams, we have to convert the objects mass from kg to g and then we can get the density.

.8kg * 1000g/kg = 800 grams

So

800g/500ml = 1.6grams/mL this is the density.

So divide the density of your object by the density of water, which is 1g/mL, you get 1.6 as the specific gravity. This means the object is 1.6 times more dense than water.

8 0

4 years ago

A rock falls off a cliff. How fast will it be going after falling for 4.33 seconds?

bixtya [17]

Answer:42.43m/s

Explanation:According to vf=vi+at, we can calculate it since v0 equals to 0. vf=0+9.8m/s^2*4.33s= 42.434m/s

4 0

1 year ago

How fast (in rpm) must a centrifuge rotate if a particle 6.00 cm from the axis of rotation is to experience an acceleration of 1

astra-53 [7]

The acceleration experienced by the particle is given by
$a=113000 g=113000 \cdot 9.81 m/s^2$
This corresponds to the centripetal acceleration of the motion, which is related to the angular speed $\omega$ of the particle and its distance r from the axis by the relationship
$a= \omega ^2 r$
In our problem, $r=6 cm=0.06 m$ , so we can solve for $\omega$ :
$\omega = \sqrt{ \frac{a}{r} } = \sqrt{ \frac{113000 \cdot 9.81 m/s^2}{0.06 m} }=4298 rad/s$
However, we must convert it into rpm (revolution per minute).
We know that 1 rad corresponds to $( \frac{1}{2 \pi} )$ revolutions, while $1 s = \frac{1}{60} min$ . So we the conversion is $\omega = 4298 rad/s \cdot ( \frac{1}{2\pi} rev/rad )( 60 s/min)=41067 rpm$

4 0

4 years ago

How can a sound of a different note be produced in a guitar without changing the length of wire?

lianna [129]

Answer:

how tightly strung the wire is

5 0

3 years ago

Read 2 more answers