1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
anastassius [24]
3 years ago
7

A moving object has a kinetic energy of 150 j and a momentum with a magnitude of 30.0 kg•m/s. determine the mass and speed of th

e object
Physics
1 answer:
SOVA2 [1]3 years ago
4 0
To determine the answer to this item, we use two (2) equations.

Equation for kinetic energy:
   KE = 0.5 mv²

Equation for momentum:
  P = mv

From the second equation, we can deduced that,
  m = P/v
Substituting the known values from the given above,

  m = 30/v

Using this expression in the first equation,

  KE = 0.5 mv²;   150 = 0.5(30/v)(v²)

The value of v from the equation is 10 m/s. 

The mass is therefore calculated as such,
  m = 30/v = 30/10 = 3 kg

Hence, the answers are,

<em> Mass  = 3 kg</em>
<em> Velocity = 10 m/s</em>
You might be interested in
Two bullets of the same size, mass and horizontal velocity are fired at identical blocks, only one is made of steel and the othe
tatiyna

Answer and Explanation:

  • Since we're discussing shots, the significant thing is the way the energy is changed over as there is deceleration of the bullet to a halt when it hits something.
  • Kinetic Energy is relative to mass times speed squared, so in reality, the 2 cases given have practically indistinguishable Kinetic energy. The measure of energy is authoritative, so the two cases will do generally a similar harm given, obviously we look at situations when all the kinetic energy is spent.
  • One contrast that will be effectively obvious is that the weapon in the case of heavy bullet will recoil more.  
  • One can consider energy assimilation as force times separation distance, and energy ingestion as a product of force and time.
  • Henceforth, the heavier yet more slow bullet with a similar energy will venture to every part of a similar separation in the engrossing material, but since of bigger force, will take a more drawn out time doing it.
  • It will along these lines, additionally, give a more noteworthy "kick" to the object that absorbs.
8 0
4 years ago
Harry is reading an online summary of the law of reflection. The site states that after light hits a mirror, the angle of reflec
tatiyna

'The normal is a line perpendicular to the surface of the mirror'.This is the correct statement that corrects an error on the site.

<h3>What is the law of reflection?</h3>

The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.

The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.

When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.

Hence 'The normal is a line perpendicular to the surface of the mirror'.This is the correct statement that corrects an error on the site

To learn more about the law of reflection refer to the link;

brainly.com/question/12029226

5 0
2 years ago
Read 2 more answers
Which three of the following are characteristics of ionic bonding?
Lyrx [107]
Gains at least one nutrient
7 0
3 years ago
A 25,000 kg traveling east collides with a 2,000 kg truck standing still on the tracks. After the collision the train and truck
Elis [28]

Answer:

24.084 m/s

Explanation:

From the law of conservation of linear momentum

Total momentum before collision equals to the total momentum after collision

Since momentum=mv where m is mass and v is velocity

M_{truck}V_{truck}=V_{common}*(M_{truck} +M_{standing}) where M_{truck} is the mass of the truck, V_{truck} is velocity of the truck, V_{common} is the common velocity of moving and standing truck after collision and M_{standing} is the mass of the standing truck

Making V_{truck} the subject we obtain

V_{truck}=\frac { V_{common}*(M_{truck} +M_{standing})}{M_{truck}}

Substituting M_{truck} as 25000 Kg, V_{common} as 22.3 m/s, M_{standing} as 2000 Kg we obtain

V_{truck}=\frac { 22.3 m/s *(25000 Kg +2000 Kg)}{25000}= 24.084 m/s

Therefore, assuming no friction and considering that after collision they still move eastwards hence common velocity and initial truck velocities are positive

The truck was moving at 24.084 m/s

3 0
3 years ago
Which group is the most common sedimentary rock
Llana [10]
Shale, sandstone, and limestone are the most commoc types of sedimentary rocks. They are formed by the most common mineral that is found on or near the surface of the Earth
4 0
3 years ago
Other questions:
  • What is the most immediate driving force behind pulmonary ventilation?
    11·1 answer
  • Protons and ____ have electric charge?
    5·2 answers
  • Una pelota rueda por una pendiente con aceleración constante. Cuando pasa por un punto P su velocidad es 1,2 ms-1 y al cabo de u
    13·1 answer
  • An automobile tire having a temperature of 3.4 ◦C (a cold tire on a cold day) is filled to a gauge pressure of 24 lb/in2 . What
    9·2 answers
  • If the net force on an object is zero then the object has
    8·1 answer
  • 9. The three types of stress that act on Earth's rocks are compression, tension, and A. strain. B. shear. C. tephra. D. shale.
    13·2 answers
  • Complete the sentence. The universal solvent is ______ .
    13·2 answers
  • (12 points) Analysis from the point where the block is released to the point where it reaches the maximum height i) Calculate th
    7·1 answer
  • Particle dislodgement in the filtration process is generally undesirable, except during?
    15·1 answer
  • solve the following system of equations using substitution x+y+z=7y=32x+y-z=5enter your answer in the form of (x,y,z)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!