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anastassius [24]
2 years ago
7

A moving object has a kinetic energy of 150 j and a momentum with a magnitude of 30.0 kg•m/s. determine the mass and speed of th

e object
Physics
1 answer:
SOVA2 [1]2 years ago
4 0
To determine the answer to this item, we use two (2) equations.

Equation for kinetic energy:
   KE = 0.5 mv²

Equation for momentum:
  P = mv

From the second equation, we can deduced that,
  m = P/v
Substituting the known values from the given above,

  m = 30/v

Using this expression in the first equation,

  KE = 0.5 mv²;   150 = 0.5(30/v)(v²)

The value of v from the equation is 10 m/s. 

The mass is therefore calculated as such,
  m = 30/v = 30/10 = 3 kg

Hence, the answers are,

<em> Mass  = 3 kg</em>
<em> Velocity = 10 m/s</em>
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A 3" diameter germanium wafer that is 0.020" thick at 300K has 1.015 x 10^17 As atoms added to it. What is the resistivity of th
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Answer:

0.546 ohm / μm

Explanation:

Given that :

N = 1.015 * 10^17

Electron mobility, u = 3900

Hole mobility, h = 1900

Ng = 4.42 x10^22

q = 1.6*10^-19

Resistivity = 1/qNu

Resistivsity (R) = 1/(1.6*10^-19 * 1.015 * 10^17 * 3900)

= 0.01578880889 ohm /cm

Resistivity of germanium :

R = 1 / 2q * sqrt(Ng) * sqrt(u*h)

R = 1 / 2 * 1.6*10^-19 * sqrt(4.42 x10^22) * sqrt(3900*1900)

R = 1 /0.0001831

R = 5461.4964 ohm /cm

5461.4964 / 10000

0.546 ohm / μm

7 0
2 years ago
A 600-kg car traveling at 30.0 m/s is going around a curve having a radius of 120 m that is banked at an angle of 25.0°. The coe
andrey2020 [161]

Answer:

The magnitude of force is 1593.4N

Explanation:

The sum of the horizontal components of the friction and the normal force will be equal to the centripetal force on the car. This can be represented as

fcostheta + Nsintheta = mv^2/r

Where F = force of friction

Theta = angle of banking

N = normal force

m = mass of car

v = velocity of car

r = radius of curve

The car has no motion in the vertical direction so the sum of forces = 0

The vertical component of the normal force acts upwards whereas the weight of the car and the vertical component friction acts downwards.

Taking the upward direction to be positive,rewrite the equation above to get:

Ncos thetha = mg - fsintheta =0

Ncistheta = mg + fain theta

N = mg/cos theta + sintheta/ costheta

fcostheta +[mg/costheta + ftan theta] sin theta = mv^2/r

Substituting gives:

f = (1/(costheta + tanthetasintheta) + mgtantheta = mv^2/r - mgtantheta)

Substituting given values into the above equation

f = 1/(cos25 + tan 25 )(sin25)[ 600×30/120 - (600×9.81)tan

f = 1593.4N25

4 0
3 years ago
Read 2 more answers
Jill does twice as much work as Jack does and in half the time. Jill's power output is Group of answer choices one-fourth as muc
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Answer:

Second Choice.

Explanation:

Jack's Power = W/t

Jill's Power = 2W/(0.5)*t

2/0.5 = 4

Jill's Power = 4*W/t

Jill's Power is 4 times greater than Jack's

Second Choice

3 0
2 years ago
If transpiration didn't take place, would water be able to enter the roots of the plant? Explain your reasoning
s2008m [1.1K]

Answer:

If transpiration didn't take place water would still be able to enter the roots of a plant

Explanation:

transpiration is the process of water leaving from living organisms to the atmosphere, therefore, if transpiration didn't occur the water would not transpire to the atmosphere and would remain in the root but water absorption would not change because it is a biological need for the living organism as such

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