Answer:
Chiral:
3-Methyl-2-butanol
Achiral:
1-Pentanol
3-Pentanol
3-Methyl-1-butanol
Explanation:
Only the molecule that bears a carbon atom surrounded by 4 different groups can be said to be Chiral, the other molecules don't satisfy this property.
Acid has a pH below 7 while water has a pH of 7. A strong acid with a pH of roughly 3, HCl is. Water gets more acidic and loses pH in the range of 4-5 when HCl is added to it.
<h3>What is pH?</h3>
A substance's pH is a gauge of how basic or acidic it is. It is a measurement of the amount of H+ present in the solution. It is equivalent to the negative logarithm of the concentration of H+ ions mathematically.
A solution is acidic if its pH value is less than 7, and basic if it is greater than 7. Acids have a lower pH because they contain more H+ ions. Strong acid hydrochloric acid has a pH between 2 and 3.
Water has no charge. Water becomes acidic in pH if any acid is introduced. Therefore, if HCl is given to water, the pH of the water will change to 3-5 depending on the acid content.
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The ansewr is A i would guess
14. a. Acidic
15. b. Weaker
16. d. Dilute and weak
Explanation:
14. Which type of the solution is one with the pH of 3?
Solution with pH from 1 to 7 are acidic, equal to 7 is neutral and from 7 to 14 basic. The solution with the pH equal to 3 is <u>acidic</u>.
15. The smaller the value of the base dissociation constant (Kb), the <u>weaker</u> the base.
The dissociation reaction of a base (B) is:
B + H₂O → BH⁺ + OH⁻
Kb is defined as:
Kb = ( [BH⁺] × [OH⁻] ) / ( [B] × [H₂O] )
The potency of the base depends on the concentration of the hydroxide ion [OH⁻], so if the Kb ratio is small it means that the concentration of hydroxide ion is smaller so the base will be <u>weaker</u>.
16. A 0.39 M solution of an acid that ionizes only slightly in solution would be termed <u>dilute and weak</u>.
The acid is weak because is only slightly ionizing in solution. The therm diluted is a little bit arbitrarily because we ask yourself "diluted in respect with what"? I would characterize the acid to be diluted at a concentration of 1 M and concentrated at a concentration of 10 M.
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pH
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Answer:
The new volume is 5.913*10^4 L
Explanation:
Step 1: Write out the formula to be used:
Using general gas equation;
P1V1 / T1 =P2V2 /T2
V2 = P1V1T2 / P2T1
Step 2: write out the values given and convert to standard unit's where necessary
P1 = 0.995atm
P2 0.720atm
V1 = 5*10^4 L
T1 = 32°C = 32+ 273 = 305K
T2 = -12°C = -12 + 273 = 261K
Step 3: Equate your values and do the calculation:
V2 = 0.995 * 5*10^4 * 261 / 0.720 * 305
V2 = 1298.475 * 10^4 / 219.6
V2 = 5.913 * 10^4 L
So the new volume of the balloon is 5.913*10^4 L
