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2 years ago

If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 Liters, what is the temperature in Kelvin(K)

Chemistry

1 answer:

kvv77 [185]2 years ago

4 0

Answer:

205 K (to 3 significant figures)

Explanation:

Assuming that 4 moles of the gas behaves like an ideal gas and obey the kinetic molecular theory.

Let's apply the ideal gas law, pV= nRT.

Here p denotes the pressure of the gas, V is for volume, n is the number of moles of the gas, R is the universal gas constant and T is the temperature.

Substitute the given information into the equation:

5.6 atm ×12 L= 4 mol ×R ×T

Since pressure is in atm and volume is in L, we can use R= 0.08206 L atm K⁻¹ mol⁻¹.

5.6 atm ×12 L= 4 mol ×0.08206 L atm K⁻¹ mol⁻¹ ×T

T= 67.2 ÷0.32824

T= 204.73 (5 s.f.)

T= 205 K (3 s.f.)

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2 years ago

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STEP III

Rewriting these in the form of equation

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____________________________

$\\$

$\mathfrak{\underline{\green{ Why\: KOH \:has\: been\: taken\: as\: aqueous ?}}}$

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