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IRISSAK [1]
3 years ago
6

If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 Liters, what is the temperature in Kelvin(K)

Chemistry
1 answer:
kvv77 [185]3 years ago
4 0

Answer:

205 K (to 3 significant figures)

Explanation:

Assuming that 4 moles of the gas behaves like an ideal gas and obey the kinetic molecular theory.

Let's apply the ideal gas law, pV= nRT.

Here p denotes the pressure of the gas, V is for volume, n is the number of moles of the gas, R is the universal gas constant and T is the temperature.

Substitute the given information into the equation:

5.6 atm ×12 L= 4 mol ×R ×T

Since pressure is in atm and volume is in L, we can use R= 0.08206 L atm K⁻¹ mol⁻¹.

5.6 atm ×12 L= 4 mol ×0.08206 L atm K⁻¹ mol⁻¹ ×T

T= 67.2 ÷0.32824

T= 204.73 (5 s.f.)

T= 205 K (3 s.f.)

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Which of the following represents the least number of molecues?
Mars2501 [29]

Answer:

Answer: a) 20g of H2O (18.02 g/mol) molecules=6.68x10^23

Explanation:

In order to find the amount of molecules of each of the options, we need to follow the following equation.

molecules=\frac{mass(g)x6.022x10^{23}(molecules/mol) }{atomic weight(g/mol)}

So, let´s get the number of molecules for each of the options.

a) molecules=\frac{20(g)x6.022x10^{23}(molecules/mol) }{18.02(g/mol)}=6.68x10^{23}molecules

b) molecules=\frac{77(g)x6.022x10^{23}(molecules/mol) }{16.06(g/mol)}=2.89x10^{24}molecules

c) molecules=\frac{68(g)x6.022x10^{23}(molecules/mol) }{42.09(g/mol)}=9.73x10^{23}molecules

d) molecules=\frac{100(g)x6.022x10^{23}(molecules/mol) }{44.02(g/mol)}=1.37x10^{24}molecules

d) molecules=\frac{84(g)x6.022x10^{23}(molecules/mol) }{20.01(g/mol)}=2.53x10^{24}molecules

the smalest number is in option a)

Best of luck.

7 0
3 years ago
A balloon contains 5 L of oxygen at a pressure of 90 kPa. How much oxygen will the balloon contain if the pressure is lowered to
laila [671]
Answer is: volume will be 6,7 L.
Boyle's Law: the pressure volume law - <span> volume of a given amount of gas held  varies inversely with the applied pressure when the temperature and mass are constant.
p</span>₁V₁ = p₂V₂.
90 kPa · 5 L = 67 kPa · V₂.
V₂ = 90 kPa · 5 L / 67 kPa.
V₂ = 6,7 L, but same amount of oxygen.


7 0
3 years ago
What mass of H2O is produced by the combustion of 1.00 mol of CH4?
kkurt [141]
CH4 : H2O
1 : 2

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number of moles of H2O = 2.00mol

mass = number of moles x molar mass

mass of H2O = 2.00 x (1 + 1 + 16)
mass of H2O = 36g
8 0
2 years ago
Describe how a baseball player accelerates as he runs around the bases after hitting home run
Wewaii [24]
<span>he accelerates when he runs  away from home plate.  as he reaches each base, the player accelerates by changing direction. he accelerates again when slowing down after reaching home plate.</span>
4 0
3 years ago
g A mass spectrum. The peak at mass 100 has a 8% relative abundance. THe peak with mass 85 has a 40% abundance. The peak at 71 h
Sati [7]

Answer:

The peak at mass 100 with a 8% relative abundance is the molecular ion peak

Explanation:

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Mass of 100 is same as mass to charge ratio =100

8 0
3 years ago
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