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Snezhnost [94]
3 years ago
8

Consider the following balanced equation: SiO2(s)+3C(s)→SiC(s)+2CO(g) Complete the following table showing the appropriate numbe

r of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product formed. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that is made.
Mol SiO2 Mol C Mol SiC Mol CO

Row 1: 3 _____ _____ _____

Row 2: _____ 6 _____ _____

Row 3: _____ _____ _____ 16

Row 4: 2.8 _____ _____ _____

Row 5: _____ 2.45 _____ _____

A. complete the first row. Express your answers using one significant figure separated by commas. Mol C, Mol SiC, Mol CO =

B. Complete the second row. Express your answers using one significant figure separated by commas. Mol SiO2, Mol SiC, Mol CO =

C. Complete the third row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =

D. Complete the fourth row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =

E. Complite the fifth row. Express your answers using three significant figures separated by commas. Mol SiO2, Mol SiC, Mol CO =
Chemistry
2 answers:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

A) 3SiO_2(s)+9C(s)\rightarrow 3SiC(s)+6CO(g)

B) 2SiO_2(s)+6C(s)\rightarrow 2SiC(s)+4CO(g)

C)8.0SiO_2(s)+24C(s)\rightarrow 8.0SiC(s)+16CO(g)

D)2.8SiO_2(s)+8.4C(s)\rightarrow 2.8SiC(s)+5.6CO(g)

E)0.816SiO_2(s)+2.45C(s)\rightarrow 0.816SiC(s)+1.63CO(g)

Explanation:

SiO_2(s)+3C(s)\rightarrow SiC(s)+2CO(g)

A) When 3 moles of silicon dioxide are present.

According to reaction 1 mole of silicon dioxide react with 3 moles of carbon to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 3 moles of silicon dioxide will react with :

\frac{3}{1}\times 3mol=9 mol of carbon

Then 3 moles of silicon dioxide will give :

\frac{1}{1}\times 3 mol= 3 mol of silicon carbide

Then 3 moles of silicon dioxide will give :

\frac{2}{1}\times 3 mol= 6 mol of carbon monoxide

3SiO_2(s)+9C(s)\rightarrow 3SiC(s)+6CO(g)

B) When 6 moles of carbon are present.

According to reaction 3 moles of carbon reacts with 1 mole of silicon dioxide react with to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 6 moles of carbon will react with :

\frac{1}{3}\times 6 mol=2 mol of silicon dioxde

Then 3 moles of carbon  will give :

\frac{1}{3}\times 6 mol= 2 mol of silicon carbide

Then 6 moles of carbon will give :

\frac{2}{3}\times 6 mol= 4 mol of carbon monoxide

2SiO_2(s)+6C(s)\rightarrow 2SiC(s)+4CO(g)

C)When 6 moles of carbon are present.

According to reaction ,1 mole of silicon carbide and 2 moles of carbon monoxide is produced when, 3 moles of carbon reacts with 1 mole of silicon dioxide reacts.

Then 16 moles of carbon monoxide will be produced from :

\frac{1}{2}\times 16 mol=8 mol of silicon dioxide

Then 16 moles of carbon monoxide will give :

\frac{3}{2}\times 16 mol= 24 mol of carbon

Along with 16 moles of carbon monoxide will give :

\frac{1}{2}\times 16 mol= 8 mol of silicon carbide

8SiO_2(s)+24C(s)\rightarrow 8SiC(s)+16CO(g)

D) When 2.8 moles of silicon dioxide are present.

According to reaction 1 mole of silicon dioxide react with 3 moles of carbon to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 2.8 moles of silicon dioxide will react with :

\frac{3}{1}\times 2.8 mol=8.4 mol of carbon

Then 2.8 moles of silicon dioxide will give :

\frac{1}{1}\times 2.8 mol= 2.8 mol of silicon carbide

Then 2.8 moles of silicon dioxide will give :

\frac{2}{1}\times 2.8 mol= 5.6 mol of carbon monoxide

2.8SiO_2(s)+8.4C(s)\rightarrow 2.8SiC(s)+5.6CO(g)

E) When 2.45 moles of carbon are present.

According to reaction 3 moles of carbon reacts with 1 mole of silicon dioxide react with to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 2.45 moles of carbon will react with :

\frac{1}{3}\times 2.45 mol=0.8166 mol of silicon dioxde

Then 3 moles of carbon  will give :

\frac{1}{3}\times 2.45 mol= 0.8166 mol of silicon carbide

Then 6 moles of carbon will give :

\frac{2}{3}\times 2.45 mol= 1.6333 mol of carbon monoxide

0.816SiO_2(s)+2.45C(s)\rightarrow 0.816SiC(s)+1.63CO(g)

Step2247 [10]3 years ago
4 0

Answer:

              mol(SiO₂)              mol(C)               mol(SiC)                    mol(CO)

Row 1:      0.8 x 10               0.9 x 10              0.3 x 10                     0.6 x 10

Row 2:     0.2 x 10               0.6 x 10              0.2 x 10                     0.4 x 10

Row 3:         8.0                   2.4 x 10                   8.0                        1.6 x 10

Row 4:         2.8                      8.4                        2.8                            5.6

Row 5:        0.816                  2.45                      0.816                         1.63

Explanation:

  • From the balanced equation:

<em>SiO₂(s) + 3C(s) → SiC(s) + 2CO(g),</em>

<em></em>

It is clear that 1.0 mole of SiO₂ reacts with 3.0 moles of C to produce 1.0 mole of SiC and 2.0 moles of CO.

  • We can complete the table of no. of moles of each component:

<em>A. complete the first row. Express your answers using one significant figure separated by commas. Mol C, Mol SiC, Mol CO =</em>

<em>3.0 moles of SiO₂:</em>

We use the triple amount of SiO₂, so we multiply the others by 3.0.

So, it will be 3.0 moles of SiO₂ with 9.0 moles of C that produce 3.0 moles of SiC and 6.0 moles of CO.

<em>B. Complete the second row. Express your answers using one significant figure separated by commas. Mol SiO2, Mol SiC, Mol CO =</em>

<em>6.0 mole of C:</em>

We use the double amount of C, so we multiply the others by 2.0.

So, it will be 2.0 moles of SiO₂ with 6.0 moles of C that produce 2.0 moles of SiC and 4.0 moles of CO.

<em>C. Complete the third row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =</em>

<em>16.0 moles of CO:</em>

We use the amount of CO higher by 8 times than that in the balanced equation, so we multiply the others by 8.0.

So, it will be 8.0 moles of SiO₂ with 24.0 moles of C that produce 8.0 moles of SiC and 16.0 moles of CO.

<em>D. Complete the fourth row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =</em>

<em>2.8 moles of SiO₂:</em>

We use the amount of SiO₂ higher by 2.8 times than that in the balanced equation, so we multiply the others by 2.8.

So, it will be 2.8 moles of SiO₂ with 8.4 moles of C that produce 2.8 moles of SiC and 5.6 moles of CO.

<em>E. Complite the fifth row. Express your answers using three significant figures separated by commas. Mol SiO2, Mol SiC, Mol CO =</em>

<em>2.45 moles of C:</em>

We use the amount of C lower by 0.8167 times than that in the balanced equation, so we multiply the others by 0.8167.

So, it will be 0.8167 moles of SiO₂ with 2.45 moles of C that produce 0.8167 moles of SiC and 1.633 moles of CO.

  • <em><u>The answers are expressed in the required significant figures in the answer part (table above).</u></em>
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Un movimiento es rectilíneo uniformemente variado, cuando la trayectoria del móvil es una línea recta y su velocidad  varia la misma cantidad en cada unidad de tiempo . Dicho de otra manera, este movimiento se caracteriza por una trayectoria que es una línea recta y la velocidad cambia su módulo de manera uniforme: aumenta o disminuye en la misma cantidad por cada unidad de tiempo. Y la aceleración es constante y no nula (diferente de cero).

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x=x0+v0*t+\frac{1}{2} *a*t^{2}

donde x es la posición del cuerpo en un instante dado, x0 la posición en el instante inicial, v0 la velocidad inicial y a la aceleración.

En este caso, por un lado podes considerar:

  • x= 90 m
  • x0= 0 m
  • v0= ?
  • t= 2
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Reemplazando obtenes:

90=v0*2+\frac{1}{2} *a*2^{2}

90=v0*2+\frac{1}{2} *a*4

90=v0*2+2*a

Y por otro lado tenes:

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  • x0= 0
  • v0= ?
  • t= 3
  • a= ?

Reemplazando obtenes:

120=v0*3+\frac{1}{2} *a*3^{2}

120=v0*3+\frac{1}{2} *a*9

120=v0*3+\frac{9}{2} *a

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\left \{ {{2*v0+2*a=90} \atop {3*v0+\frac{9}{2} *a=120}} \right.

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v0= \frac{90-2*a}{2}

Reemplazando en la segunda ecuación:

120=\frac{90-2*a}{2} *3+\frac{9}{2} *a

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Condensation polymers are formed by the joining of two or more molecules  to form polymers with the elimination of a small molecule.

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