1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Snezhnost [94]
3 years ago
8

Consider the following balanced equation: SiO2(s)+3C(s)→SiC(s)+2CO(g) Complete the following table showing the appropriate numbe

r of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product formed. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that is made.
Mol SiO2 Mol C Mol SiC Mol CO

Row 1: 3 _____ _____ _____

Row 2: _____ 6 _____ _____

Row 3: _____ _____ _____ 16

Row 4: 2.8 _____ _____ _____

Row 5: _____ 2.45 _____ _____

A. complete the first row. Express your answers using one significant figure separated by commas. Mol C, Mol SiC, Mol CO =

B. Complete the second row. Express your answers using one significant figure separated by commas. Mol SiO2, Mol SiC, Mol CO =

C. Complete the third row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =

D. Complete the fourth row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =

E. Complite the fifth row. Express your answers using three significant figures separated by commas. Mol SiO2, Mol SiC, Mol CO =
Chemistry
2 answers:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

A) 3SiO_2(s)+9C(s)\rightarrow 3SiC(s)+6CO(g)

B) 2SiO_2(s)+6C(s)\rightarrow 2SiC(s)+4CO(g)

C)8.0SiO_2(s)+24C(s)\rightarrow 8.0SiC(s)+16CO(g)

D)2.8SiO_2(s)+8.4C(s)\rightarrow 2.8SiC(s)+5.6CO(g)

E)0.816SiO_2(s)+2.45C(s)\rightarrow 0.816SiC(s)+1.63CO(g)

Explanation:

SiO_2(s)+3C(s)\rightarrow SiC(s)+2CO(g)

A) When 3 moles of silicon dioxide are present.

According to reaction 1 mole of silicon dioxide react with 3 moles of carbon to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 3 moles of silicon dioxide will react with :

\frac{3}{1}\times 3mol=9 mol of carbon

Then 3 moles of silicon dioxide will give :

\frac{1}{1}\times 3 mol= 3 mol of silicon carbide

Then 3 moles of silicon dioxide will give :

\frac{2}{1}\times 3 mol= 6 mol of carbon monoxide

3SiO_2(s)+9C(s)\rightarrow 3SiC(s)+6CO(g)

B) When 6 moles of carbon are present.

According to reaction 3 moles of carbon reacts with 1 mole of silicon dioxide react with to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 6 moles of carbon will react with :

\frac{1}{3}\times 6 mol=2 mol of silicon dioxde

Then 3 moles of carbon  will give :

\frac{1}{3}\times 6 mol= 2 mol of silicon carbide

Then 6 moles of carbon will give :

\frac{2}{3}\times 6 mol= 4 mol of carbon monoxide

2SiO_2(s)+6C(s)\rightarrow 2SiC(s)+4CO(g)

C)When 6 moles of carbon are present.

According to reaction ,1 mole of silicon carbide and 2 moles of carbon monoxide is produced when, 3 moles of carbon reacts with 1 mole of silicon dioxide reacts.

Then 16 moles of carbon monoxide will be produced from :

\frac{1}{2}\times 16 mol=8 mol of silicon dioxide

Then 16 moles of carbon monoxide will give :

\frac{3}{2}\times 16 mol= 24 mol of carbon

Along with 16 moles of carbon monoxide will give :

\frac{1}{2}\times 16 mol= 8 mol of silicon carbide

8SiO_2(s)+24C(s)\rightarrow 8SiC(s)+16CO(g)

D) When 2.8 moles of silicon dioxide are present.

According to reaction 1 mole of silicon dioxide react with 3 moles of carbon to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 2.8 moles of silicon dioxide will react with :

\frac{3}{1}\times 2.8 mol=8.4 mol of carbon

Then 2.8 moles of silicon dioxide will give :

\frac{1}{1}\times 2.8 mol= 2.8 mol of silicon carbide

Then 2.8 moles of silicon dioxide will give :

\frac{2}{1}\times 2.8 mol= 5.6 mol of carbon monoxide

2.8SiO_2(s)+8.4C(s)\rightarrow 2.8SiC(s)+5.6CO(g)

E) When 2.45 moles of carbon are present.

According to reaction 3 moles of carbon reacts with 1 mole of silicon dioxide react with to give 1 mole of silicon carbide and 2 moles of carbon monoxide.

Then 2.45 moles of carbon will react with :

\frac{1}{3}\times 2.45 mol=0.8166 mol of silicon dioxde

Then 3 moles of carbon  will give :

\frac{1}{3}\times 2.45 mol= 0.8166 mol of silicon carbide

Then 6 moles of carbon will give :

\frac{2}{3}\times 2.45 mol= 1.6333 mol of carbon monoxide

0.816SiO_2(s)+2.45C(s)\rightarrow 0.816SiC(s)+1.63CO(g)

Step2247 [10]3 years ago
4 0

Answer:

              mol(SiO₂)              mol(C)               mol(SiC)                    mol(CO)

Row 1:      0.8 x 10               0.9 x 10              0.3 x 10                     0.6 x 10

Row 2:     0.2 x 10               0.6 x 10              0.2 x 10                     0.4 x 10

Row 3:         8.0                   2.4 x 10                   8.0                        1.6 x 10

Row 4:         2.8                      8.4                        2.8                            5.6

Row 5:        0.816                  2.45                      0.816                         1.63

Explanation:

  • From the balanced equation:

<em>SiO₂(s) + 3C(s) → SiC(s) + 2CO(g),</em>

<em></em>

It is clear that 1.0 mole of SiO₂ reacts with 3.0 moles of C to produce 1.0 mole of SiC and 2.0 moles of CO.

  • We can complete the table of no. of moles of each component:

<em>A. complete the first row. Express your answers using one significant figure separated by commas. Mol C, Mol SiC, Mol CO =</em>

<em>3.0 moles of SiO₂:</em>

We use the triple amount of SiO₂, so we multiply the others by 3.0.

So, it will be 3.0 moles of SiO₂ with 9.0 moles of C that produce 3.0 moles of SiC and 6.0 moles of CO.

<em>B. Complete the second row. Express your answers using one significant figure separated by commas. Mol SiO2, Mol SiC, Mol CO =</em>

<em>6.0 mole of C:</em>

We use the double amount of C, so we multiply the others by 2.0.

So, it will be 2.0 moles of SiO₂ with 6.0 moles of C that produce 2.0 moles of SiC and 4.0 moles of CO.

<em>C. Complete the third row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =</em>

<em>16.0 moles of CO:</em>

We use the amount of CO higher by 8 times than that in the balanced equation, so we multiply the others by 8.0.

So, it will be 8.0 moles of SiO₂ with 24.0 moles of C that produce 8.0 moles of SiC and 16.0 moles of CO.

<em>D. Complete the fourth row. Express your answers using two significant figures separated by commas. Mol SiO2, Mol C, Mol SiC =</em>

<em>2.8 moles of SiO₂:</em>

We use the amount of SiO₂ higher by 2.8 times than that in the balanced equation, so we multiply the others by 2.8.

So, it will be 2.8 moles of SiO₂ with 8.4 moles of C that produce 2.8 moles of SiC and 5.6 moles of CO.

<em>E. Complite the fifth row. Express your answers using three significant figures separated by commas. Mol SiO2, Mol SiC, Mol CO =</em>

<em>2.45 moles of C:</em>

We use the amount of C lower by 0.8167 times than that in the balanced equation, so we multiply the others by 0.8167.

So, it will be 0.8167 moles of SiO₂ with 2.45 moles of C that produce 0.8167 moles of SiC and 1.633 moles of CO.

  • <em><u>The answers are expressed in the required significant figures in the answer part (table above).</u></em>
You might be interested in
Calculate the ph of a 0.17 m solution of c6h5nh3no3 (kb for c6h5nh2 = 3.8 x 10-10). record your ph value to 2 decimal places.
MatroZZZ [7]
<span>Mass of the solution = 0.17m
 Kb for C6H5NH2 = 3.8 x 10^-10
 We know Ka for C6H5NH2 = 1.78x10^-11
  We have Kw = Ka x Kb => Ka = Kw / Kb
  => (C2H5NH2)(H3O^+)/(C2H5NH3^+) => 1.78x10^-11 = K^2 / 0.17
 K^2 = 3 x 10^-12 => K = 1.73 x 10^-6.
 pH = -log(Kw(H3O^+)) = -log(1.73 x 10^-6) = 5.76</span>
6 0
3 years ago
The equilibrium constant for the reaction 2NO2(g) N2O4(g) is Keq = . If a sample at equilibrium was found to contain 0.058 M NO2
Sladkaya [172]

Answer:

\boxed{3.6}

Explanation:

                  2NO₂ ⇌ N₂O₄

E/mol·L⁻¹:   0.058     0.012

K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6} \\\\

\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}

7 0
3 years ago
Which of the following correctly applies to a catalyst? a. They do not actually participate in the chemical reaction and therefo
lawyer [7]

Answer: option B) They provide an alternate lower energy mechanism by which the reaction proceeds

Explanation:

Catalyst are involved in chemical reaction increasing the rate they occur by lowering the activation energy found in the bound- reactants complex.

The reaction moves forward because the lower energy mechanism when catalyst are added allows for a more easily splitted bond, thus, allowing the formation of products.

6 0
3 years ago
Enter the electron configuration for I+ using noble gas shorthand notation.
Maurinko [17]

Answer:

[Kr] 4d10 5s2 5p4

Explanation:

The Symbol I represents Iodine. It has atomic number of 53. The full electronic configuration is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p5

However the question requested for the configuration of I+.

I+ is a cation and it simply refers to an iodine atom that has lost a single electron. The electronic configuration of I+ is given as;

1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p4

Using Noble gas shorthand representation, we have;

[Kr] 4d10 5s2 5p4

6 0
2 years ago
What does the atomic number tell you about an atomwhat two particles add up to equal the mass number?
Lubov Fominskaja [6]
The atomic number is the number of the protons in an atom the two particles that add up to equal the mass is the protons and neutrons
8 0
3 years ago
Other questions:
  • What does the color red means
    11·2 answers
  • In a separate experiment beginning from the same initial conditions, including a temperature Ti of 25.0°C, half the number of mo
    10·1 answer
  • Into which molecule are all the carbon atoms in glucose ultimately incorporated during cellular respiration?
    15·1 answer
  • Why do you use the same amount of water for each shape of ice?
    9·1 answer
  • Which two types of consumers are known as “nature’s clean-up crew”? Why are they important?
    9·2 answers
  • What happens when an electron moves from n=2 to n=5?
    11·1 answer
  • Why is Anton Von Leeuwenhoek important in the cell theory?​
    13·1 answer
  • What are the common Hazard and Risk?​
    13·2 answers
  • What are two possible ways to show the structure of ch4?
    12·2 answers
  • Elemental sulfur is one of the products of the gas-phase reaction of nitric acid and hydrogen sulfide. The other
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!