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ra1l [238]
3 years ago
7

A 920-kg compact car moving at 92 m/s has approximately 3,893,440 Joules of kinetic energy. What is the change in kinetic energy

if it is moving at 36 m/s?
Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

Change in kinetic energy = 3297280 J

Explanation:

Given that,

Mass, m = 920 kg

Speed of a car, v = 92 m/s

Kinetic energy, K = 3,893,440 J

If the speed of a car, V = 36 m/s

Net kinetic energy is given by :

K_n=\dfrac{1}{2}mV^2\\\\=\dfrac{1}{2}\times 920\times (36)^2\\\\K_n=596160\ J

The change in kinetic energy = 3,893,440 - 596160

= 3297280 J

So, the change in kinetic energy of the car is 3297280 J.

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A magnetic field has a magnitude of 1.2 \times 10^{-3} T, and an electric field has a magnitude of 4.6 \times 10^{3}N/C. Both fi
lana66690 [7]

Answer: F = 113.4.10^{-3}N

Explanation: Net Force is the total forces acting in an object. In this case, there are two forces acting on the charge: one due to magnetic field (Fm) and another due to electric field (Fe). So, net force is

F = Fe + Fm

Force due to electric field

To determine this force:

Fe = q.E, where q is the charge and E is electric field.

Calculating:

Fe = q.E

Fe = 1.8.10^{-6}.4.6.10^{3}

Fe = 8.28.10^{-3}N

Force due to magnetic field: It can only happens when the charge is in movement, so

Fm = q.(v×B), where v represents velocity and B is magnetic field

The cross product indicates that force is perpendicular to the velocity and the field.

Calculating:

Fm = q.v.B.senθ

As θ=90°,

Fm = q.v.B

Fm =  1.8.10^{-6}.3.1.10^{6}.1.2.10^{-3}

Fm = 6.696.10^{-3}N

F, Fm and Fe make a triangle. So, using Pythagorean theorem:

F = \sqrt{Fe^{2} + Fm^{2} }

F = \sqrt{(8.28.10^{-3} )^{2} +(6.696.10^{-3} )^{2} }

F = 113.4.10^{-3}N

The net force acting on the charge is F = 113.4.10^{-3}N

4 0
3 years ago
Suppose you are asked to find the amount of time t, in seconds, it takes for the turntable to reach its final rotational speed.
Annette [7]

Answer:

option (D)

Explanation:

Here initial rotation speed is given, final rotation speed is given and asking for time.

If we use

A) θ=θ0+ω0t+(1/2)αt2

For this equation, we don't have any information about the value of angular displacement and angular acceleration, so it is not useful.

B) ω=ω0+αt

For this equation, we don't have any information about angular acceleration, so it is not useful.

C) ω2=ω02+2α(θ−θ0)

In this equation, time is not included, so it is not useful.

D) So, more information is needed.

Thus, option (D) is true.

5 0
3 years ago
A 20kg mass approaches a spring at a speed of 30 m/s. The mass compresses the spring 12cm before coming to a stop. Calculate the
Oksana_A [137]

Answer:

625000 N/ m

Explanation:

m= 20 kg

v= 30 m/s

x= 12 cm

k = ?

Here when the mass when hits at spring its speed is

Vi= 30 m/s

Finally it comes to rest after compressing for 12 cm

i-e Vf = 0 m/s

Distance= S= 12 cm = 0.12 m

using

2aS= Vf2 - Vi2

==> 2a ×0.12 = o- 30 × 30

==> a = 900 ÷ 0.24 = 3750 m/sec2

Now we know;

F = ma

F= -Kx

==> ma= -kx

==> 20 × 3750 = -K × 0.12

==> k = 625000 N/ m

5 0
3 years ago
what is the frequency of a ocean wave that is traveling at a speed of 45 m/s if it has a wavelength of 3 meters? please show wor
Varvara68 [4.7K]

Answer: Frequency = 15Hz

Explanation:

Given that

Wavelength (λ) = 3 m

Wave speed V = 45 m/s

Wave speed is the product of frequency and wavelength. That is

V = f(λ)

Substitute wavelength and wave speed into the formula

45 = f × 3

Make f the subject of the formula

f = 45/3

f = 15 Hz

Therefore, the frequency of the ocean wave is 15 Hz

8 0
4 years ago
Dominic made the table below to organize his notes about mixtures.
Andrei [34K]

Answer:

Althought it us possible to have more then one state, it's also possible to have only one state of matter

Explanation:

You can make solutions of only one state if matter, for example , it two liquids can be mixed to form a solution they are called miscible.

4 0
3 years ago
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